Four persons are to be choosen from a group of 3 men, 2 women and 4 children. Find the probability of selecting 1 man,1 woman and 2 children.

Correct Answer: 2/7

Explanation:

Total number of persons = 9

Out of 9 persons 4 persons can be selected in $9 C 4$ ways =126

1 man,1 woman and 2 children can be selected in $3 C 1 * 2 C 1 * 4 C 1$ ways =36
So,required probability = 36/126 =2/7

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