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A fair six-sided die is rolled twice. What is the probability of getting 4 on the first roll and not getting 6 on the second roll ?

Correct Answer: 5/36

Explanation:

The two events mentioned are independent.


The first roll of the die is independent of the second roll. Therefore the probabilities can be directly multiplied.


P(getting first 4) = 1/6


P(no second 6) = 5/6


Therefore P(getting first 4 and no second 6) = 1/6 x 5/6 = 5/36


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