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- Question
The probabilities that A and B will tell the truth are 2 / 3 and 4 / 5 respectively . What is the probability that they agree with each other ?
Options- A. 3/5
- B. 1/3
- C. 2/5
- D. 3/4
- Correct Answer
- 3/5
ExplanationLet A be the event of A will tell truth. B be the event of B tell truth
When both agree then they say true or they say false together, that is
Also these events will be mutually exclusive :
- 1. One card is drawn from a pack of 52 cards,each of the 52 cards being equally likely to be drawn.Find the probability that the ball drawn is an ace :
Options- A. 1/13
- B. 1/12
- C. 1/14
- D. 1/15 Discuss
- 2. An unbiased cubic die is thrown.What is the probabiltiy of getting a multiple of 3 or 4?
Options- A. 1/12
- B. 1/9
- C. 3/4
- D. 1/2 Discuss
- 3. A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is:
Options- A. 2/13
- B. 1/13
- C. 1/26
- D. 1/52 Discuss
- 4. There are 10 Letters and 10 correspondingly 10 different Address. If the letter are put into envelope randomly, then find the Probability that Exactly 9 letters will at the Correct Address ?
Options- A. 1/10
- B. 1/9
- C. 1
- D. 0 Discuss
- 5. Consider 5 independent Bernoulli?s trials each with probability of success p. If the probability of at least one failure is greater than or equal to 31/32 , then p lies in the interval ?
Options- A. [1, 32]
- B. (0, 1)
- C. [1, 1/2]
- D. (1, 1/2] Discuss
- 6. Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5 ?
Options- A. 2/3
- B. 1/2
- C. 7/8
- D. 4/5 Discuss
- 7. Three fair coins are tossed simultaneously. Find the probability of getting more heads than the number of tails
Options- A. 2
- B. 7/8
- C. 5/8
- D. 1/2 Discuss
- 8. A number is selected from the numbers 1,2,3,4.......25.The probability for it to be divisible by 4 or 7 is:
Options- A. 3/25
- B. 9/25
- C. 1/25
- D. None of these Discuss
- 9. Four persons are to be choosen from a group of 3 men, 2 women and 4 children. Find the probability of selecting 1 man,1 woman and 2 children.
Options- A. 2/7
- B. 3/7
- C. 4/7
- D. 3/7 Discuss
- 10. Two unbiased coin are tossed. What is the probability of getting atmost one head?
Options- A. 1/2
- B. 3/2
- C. 1/6
- D. 3/4 Discuss
Probability problems
Search Results
Correct Answer: 1/13
Explanation:
Total number of events=52
Number of aces =4
So,required probability = 4/52 =1/13
Correct Answer: 1/2
Explanation:
Total numbers in a die=6
P(mutliple of 3) = 2/6 = 1/3
P(multiple of 4) = 1/6
P(multiple of 3 or 4) = 1/3 + 1/6 = 1/2
Correct Answer: 1/26
Explanation:
Here, n(S) = 52.
Let E = event of getting a queen of club or a king of heart.
Then, n(E) = 2.
P(E) =n(E)/n(S)=2/52=1/26.
Correct Answer: 0
Explanation:
As we know we have 10 letter and 10 different address and one more information given that exactly 9 letter will at the correct address....so the remaining one letter automatically reach to their correct address
P(E) = favorable outcomes /total outcomes
Here favorable outcomes are '0'.
So probability is '0'.
Correct Answer: [1, 1/2]
Explanation:
Probability of atleast one failure
= 1 - no failure > 31/32
= 1 -
> 31/32
=
1/32
= p < 1/2
Also p > 0
Hence p lies in [0,1/2].
Correct Answer: 1/2
Explanation:
Multiples of 3 below 20 are 3, 6, 9, 12, 15, 18
Multiples of 5 below 20 are 5, 10, 15, 20
Required number of possibilities = 10
Total number of possibilities = 20
Required probability = 10/20 = 1/2.
Correct Answer: 1/2
Explanation:
S = { HHH, HHT, HTH, HTT, THH, THT, TTH, TTT }
=> n(S) = 8
E = { HHH, HHT, HTH, THH }
=> n(E) = 4
P(E) = 4/8 = 1/2
Correct Answer: 9/25
Explanation:
Total numbers = 25
Numbers divisible by 4 or 7 are 4, 7, 8, 12, 14, 16, 20, 21, 24 = 9
The probability (divisible by 4 or 7) = 9/25
Correct Answer: 2/7
Explanation:
Total number of persons = 9
Out of 9 persons 4 persons can be selected in ways =126
1 man,1 woman and 2 children can be selected in
ways =36
So,required probability = 36/126 =2/7
Correct Answer: 3/4
Explanation:
Here, S={HH,HT,TH,TT}
Let E be the event of getting one head
E={TT,HT,TH}
P(E )= n(E)/n(S) =3/4
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