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Three fair coins are tossed simultaneously. Find the probability of getting more heads than the number of tails

2
7/8
5/8
1/2

Correct Answer: 1/2

Explanation:

S = { HHH, HHT, HTH, HTT, THH, THT, TTH, TTT }

=> n(S) = 8

E = { HHH, HHT, HTH, THH }

=> n(E) = 4

P(E) = 4/8 = 1/2

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