Home » Aptitude » Probability

Three fair coins are tossed simultaneously. Find the probability of getting more heads than the number of tails

Correct Answer: 1/2

Explanation:

S = { HHH, HHT, HTH, HTT, THH, THT, TTH, TTT }


=> n(S) = 8


E = { HHH, HHT, HTH, THH }


=> n(E) = 4


P(E) = 4/8 = 1/2


← Previous Question Next Question→

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion