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A bag contains 8 red and 4 green balls. Find the probability that two balls are red and one ball is green when three balls are drawn at random.

56/99
112/495
78/495
None of these

Correct Answer: 112/495

Explanation:

$n S = C 412 = 495$

$n E = C 28 \times C 14 = 112$

$∴ P (E) = \frac{112}{495}$

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