The original fraction is = 15/17.
Total money = Rs.[600*(25/100)+1200*(50/100)]= Rs. 750.
25 paise coins removed = Rs. (600*12/100) = 72.
50 paise coins removed = Rs. (1200*24/100)= 288.
Money removed =Rs.(72*25/100+288*50/100) = Rs.162.
Required percentage = (162/750*100)% = 21.6 %.
Let the orginal salary = Rs. 100. New's salary = Rs.120.
Decrease on 120 = 20. Decrease on 100 = [(20/120)*100]% = (16 + 2/3) %.
Lets say shyam sells at 100,
Since Ram sells 25% cheaper than Shyam,
Therefor Ram sells at less than 25% of100 or 75 rs.
Ram sells 25% dearer than Bram or 125% of Ram =100% of Bram or
125% of x (say x price of bram )=75rs.
or 100% of x =60rs.
hence price of bram is 60rs.
now Bram's good is cheaper than Shyam's as (100-60)x100/100% or 40%.
Hence Brams Good is 40% cheaper than that of Shyam's good.
Let the large number be x.
Then x - 20 = 20x/100
=> x - x/5 = 20 => x = 25.
Let the number of candidates appeared from each state be x.
In state A, 6% candidates got selected from the total appeared candidates
In state B, 7% candidates got selected from the total appeared candidates
But in State B, 80 more candidates got selected than State A
From these, it is clear that 1% of the total appeared candidates in State B = 80
=> total appeared candidates in State B = 80 x 100 = 8000
=> total appeared candidates in State A = total appeared candidates in State B = 8000
We have : x + (x% of 150 )= 150
=> x+(x/100)*150] = 150
=>
=> x = (150*2)/5 = 60
Total number of sweets
= 80 x 15 x 80/100 + 5 x 80 x 25/100
= 960 + 100 = 1060
A day has 24 hrs
=> If 24 hrs - 100
Then 1 hr = ?
100/24 = 4.16%
Let the number be x. Then, x-(2/5)x = 510
=> 3x/5 =510
=>x =[510 * ( 5/3)] =850
10 % 0f 850 = 85.
Here, x = 20 and y = - 20
Therefore, the net % change in value
=
%
=
% or - 4%
Since the sign is negative, there is a decrease in value by 4%.
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