A, B and C enter into a partnership and their shares are in the ratio 1/2 : 1/3 : 1/4. After 2 months, A withdraws half of his capital and after 10 months, a profit of Rs. 378 is divided among them. What is B's share ?

Let, Sum = P
Then S.I = P/2
Rate = 8%
and Time = 6 years
But P/2 = (P x 8 x 6) /100 (Not possible )
Thus, data is inadequate.

? = 6888.009 - 487.999 - 87.989
? ? ? 6888 - 488 - 88
? ? ? 6888 - 576 ? ? ? 6312 ? 6310

Let the speed in still water be x km/hr
Then, 6/x + 4 + 6/x - 4 = 2
? 6[ x - 4 + x + 4] = 2(x² - 16)
? x² - 6x - 16 = 0
? (x - 8) (x + 2) = 0
? x = 8 km/hr

Let the width of the room be x members
Then, its area = (4x) m²

Area of each new square room = (2x)m²
Let the side of each new room = y meters
Then, y² = 2x
Clearly, 2x is a complete square when x=2
? y² = 4
? y = 2 m .

Average rate of interest = (100 * 750) / (5000 * 3) = 5% per annual
Investment at 3% per annual = 3 / (3 + 2) × 5000 = Rs. 3000 Investment at 8% per annual = 2 / (3 + 2) × 5000 = Rs. 2000

The difference counts only due to 40% of the profit which was distributed according to their investments.

Let total profit = R.
40% of R is distributed in the ratio, 125000 : 85000 = 25 : 17

Share of 1st partner = 40% of R x25/(25 + 17)
= 40% of 25R/42 = (40/100) x (25R/42) = 5R/21

Share of 2nd partner
= 40% of 17R/42 = (40/100) x (17R/42) = 17R/105

Now according to the question
5R/21 - 17R/105 = 600
? R(25 - 17)/105 = 600
? R = (600 x 105)/8
= ? 7875

Speed of train in m/sec = 72 km/hr x 5/18 = 20 m/sec

Distance covered in meter = Time taken in crossing the platform in sec x speed in meter = 30 sec x 20 m/sec = 600m

Now, we know , Distance covered by train in crossing the platform = Length of train + Length of Platform
Therefore, length of the train = 600m - 400m = 200m

Let the number of wickets taken before the last match = y
Bowler's overall average = total run scored / total wicket taken by bowler
Then, (12.4y + 26 ) / (y + 5) = 12
? x = 85