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  • Question
  • If 1/a+1/b+1/c = 1/(a+b+c) where a+b+c not equals '0', abc not equals '0', What is the value of (a+b) (b+c) (a+c) ?


  • Options
  • A. 3
  • B. 2
  • C. 1
  • D. 0

  • Correct Answer


  • Explanation

    Let assume the value of a,b &c that will satisfy the equation.
    so a=1,b=1,c= -1 or a=1,b= -1 &c=1 or a= -1,b=1,c=1
    here all three cases satisfy the equation
    assume any one a=1,b=1,c= -1

    Hence (a+b)(b+c)(c+a)=(1+1)(1-1)(-1+1) = 0

  • Tags: AIEEE, Bank Exams, CAT, GATE, Bank Clerk, Bank PO

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    • Options
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    • Options
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