(3x + 2) (2x - 5) = ax² + kx + n. What is the value of a - n + k ?

(3x + 2) (2x - 5) =  $ax2+kx+n$ ...............(1)

But (3x + 2)(2x - 5) =  $6x2-11x-10$........(2)

so by comparing (1) & (2),

we get a= 6, k= -11 , n= -10

(a - n + k) = 6 + 10 - 11 = 5.