For dividing 12 into two whole numbers, the sum of the terms of the ratio must be a factor of 12. so, they cannot be in the ratio 3 :2.
Given number series is 514 470 ? 415 404
Here the pattern it follows is
514
514 - 44 = 470
470 - 33 = 437
437 - 22 = 415
415 - 11 = 404
Hence, the missing number in the given number series is 437.
Let 0.8 : 0.2 : : 0.2 : N
Then 0.8 x N = 0.2 x 0.2
? N = ( 0.2 x 0.2) / 0.8 = 0.04 / 0.08 = 4/80 = 0.05
Given Number series is :
3 4 14 48 576 27648
It follows a pattern that,
3
4
4 x 3 = 12 but not 14
12 x 4 = 48
48 x 12 = 576
576 x 48 = 27648
Hence, the odd one in the given Number Series is 14.
Here the given number series is 6, 3, 3, 4.5, 10
The odd one in the given series is 10
The pattern it follows is
6
6 x 0.5 = 3
3 x 1 = 3
3 x 1.5 = 4.5
4.5 x 2 = 9
Hence, the odd number is 10.
Let the number be N,
From question, (6 + N) / (14 + N) = (18 + N) / (38 + N)
? (6 + N) x (38 + N ) = (18 + N ) x (14 + N )
? N2 + 44N + 228 = N2 + 32N + 252
? 12N = 24
? N = 2
Let the total profit be Rs. 100.
After paying to charity, A's share = (95*3/5) = Rs. 57.
If A's share is Rs. 57, total profit = Rs. 100.
If A's share is Rs. 855, total profit = (100/57*855) = 1500.
Let their initial investments be x, 3x and 5x respectively. Then,
A:B:C = (x*4+2x*8) : (3x*4+(3x/2)*8) : (5x*4+(5x/2)*8)
20x : 24x : 40x = 5 : 6 : 10
Let the total profit be Rs. z. Then,
B's share = Rs. 2z/3, A's share = Rs. ( z - 2z/3 ) = Rs. z/3.
A : B = z/3 : 2z/3 = 1:2
Let the total capital be Rs, X and suppose B's money was used for x months. Then.
(1(x) / 4 * 15) / (3x) / 4 * y) = 1/2 <=> y = (15 * 2 / 3) = 10 .
Thus, B's money was used for 10 months.
Let 2A = 3B = 4C = x
Then A = x/2, B = x/3 and C = x/4
? A : B : C = x/2 : x/3 : x/4
Hence A : B : C = 6 : 4 : 3
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