16 June, 1993 = (1992 years + Period from 1.1.1993 to 16.6.1993)
Odd days in 1600 years = 0
Odd days in 300 years = 1
92 years = (69 ordinary years + 23 leap year) = (69 x 1 + 23 x 2)= 3 odd days
Jan. Feb. March April May June
(31 + 28 + 31 + 30 + 31 + 16 ) = 167 days
167 days = (23 weeks + 6 days) =6 odd days.
Total number of odd days = (0 + 1 + 3 + 6) = 3 odd days.
Given day is Wednesday.
Given year 1856, when divided by 4 leaves a remainder of 0.
NOTE: When remainder is 0, 28 is added to the given year to get the result.
So, 1856 + 28 = 1884
9th May, 2001 = (2000 years + Period from 1.1.2001 to 9.5.2001)
Odd days in 1600 years = 0
Odd days in 400 years = 0
Jan. Feb. March April May
(31 + 28 + 31 + 30 + 9) = 129 days
129 days = (18 weeks + 3 day)= 3 odd day.
Total number of odd days = (0 + 0 + 3 ) = 3 odd day.
Given day is Wednesday.
The year 1985 is an ordinary year. So, it has 1 odd day.
So, the day on 19th June, 1985 will be 1 day after the day on 19th June, 1984.
But, 19th June,1984 is Monday
S0, 19th June, 1985 is Tuesday.
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