The average age of the district level hockey team of eleven is 22 years.The average age gets increased by 1 year when the coach age is also included.what is the age of the coach ?

Given Expression 112/?196 x ?579/12 x ?256/8
=(112/14) x (24/12) x (16/8)
= 32

Marks secured by Anirudh = [(85/100) x 100] + [(70/100) x 120] + [(65/100) x 140] + [(60/100) x 160]
= (85 + 84 + 91 + 96) = 356
? Required percentage = [356/(100 + 120 + 140 + 160)] x 100 %
= (356/520) x 100% = 68⁶/₁₃%

Number of student who speak only English =30% of 60 = 18
Number of student who speak Hindi and English =20% of 60 =12
?Number of student who speak only Hindi = (60 - 30) = 30
?Number of student who speak Hindi = 30 + 12 = 42

The volume of the original cone is V = (?R²h)/3
The height and the radius of the smaller cone are 2h/3 and 2R/3, respectively
? 1/3? (2R/3)² x 2h/3 = 8V/27
? Volume of the frustum = (V - 8V/27) = 19V/27
So, the required ratio is 8 : 19 .

As per given figure , we can see that
Since the diagonals of a rectangle are equal and bisect each other. Let AC and BD intersect at M. Therefore M is the mid-point of AC and BD and AM = DM
From ?AOC, OA² + OC² = 2(AM² + MO²) [Appollonius Theorem.] .......... ( 1 )
also in ?ODB, OB² + OD² = 2(MO² + DM²) = 2(MO² + AM²) .......... ( 2 )
From equations ( 1 ) and ( 2 ) .
? OA² + OC² = OB² + OD².

Let us assume the numbers are a and b.
According to question,
a² - b² = 256000 .......................(1)
and a + b = 1000 .........................(2)
On dividing the Equation (1) with Equation (2),
(a² - b²)/(a + b) = 256000/1000
(a² - b²)/(a + b) = 256
(a + b)(a - b)/(a + b) = 256
a - b = 256...............................(3)
Add the equation (2) and (3), we will get
a + b + a - b = 1000 + 256
2a = 1256
a = 628
Put the value of a in equation (2), we will get
658 + b = 1000
b = 1000 - 628
b = 372
So answer is 628 , 372.