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- Question
A man walking at the speed of 4 kmph crosses a square field diagonally in 3 meters.The area of the field is
Options- A. 10000
- B. 20000
- C. 30000
- D. 40000
- Correct Answer
- 20000
Explanationspeed of the man = 4 x (5/18) m/sec = 10/9 m/sec
time taken = 3 x 60 sec = 180 sec
length of diagonal = speed x time = (10/9) x 180 = 200m
Area of the field = (1/2) x (dioagonal)²
= (1/2) x 200 x 200 sq.m = 20000sq.m
- 1. Let A(O,-1), B(0,3) and C(2,1) be three points. Let ?1 be the area of the triangle ABC and ?2 be the area of the triangle formed by the mid points of the sides of the triangle whose vertices are A, B and C such that ?1 =1 , ?2=x Find the value of x .
Options- A. 4
- B. 5
- C. 2
- D. 3 Discuss
- 2. If a 36 cm thread is used to wrap a book, lengthwise twice and breadth wise once, what is the size of the book ?
Options- A. 288 sq.cm
- B. 188 sq.cm
- C. 144 sq.cm
- D. 244 sq.cm Discuss
- 3. The perimeter of a square is equal to twice the perimeter of a rectangle of length 8cm and breadth 7cm. What is the circumference of a semicircle whose diameter is equal to the side of the square ?
Options- A. 55.12 cm
- B. 22.54 cm
- C. 42.51 cm
- D. 38.57 cm Discuss
- 4. The length of the rectangle is 20% more than its breadth . what will be the ratio of the area of the rectangle to that of the square whose side is equal to the breadth of the rectangle?
Options- A. 2:1
- B. 5:6
- C. 6:5
- D. data is inadequate Discuss
- 5. Wheels of diameters 7cm and 14cm start rolling simultaneously from x & y which are 1980 cm apart towards each other in opposite directions. Both of them make the same number of revolutions per second. If both of them meet after 10seconds.The speed of the smaller wheel is
Options- A. 22m/s
- B. 33m/s
- C. 44m/s
- D. 55m/s Discuss
- 6. The length of a rectangular plot is 20 meters more than its breadth. If the cost of fencing the plot @ 26.50 per meter is Rs. 5300. What is the length of the plot in meter?
Options- A. 40m
- B. 50m
- C. 60m
- D. 10m Discuss
- 7. If the ratio of two squares is 225:256,then the ratio of the perimeters is
Options- A. 25:16
- B. 15:16
- C. 16:15
- D. 17:16 Discuss
- 8. The area of a square is 1024 sq.cm. What is the ratio of the length to the breadth of a rectangle whose length is twice the side of the square and breadth is 12 cm less than the side of this square ?
Options- A. 14:9
- B. 13:12
- C. 16:5
- D. 17:13 Discuss
- 9. A rectangular grassy plot 120 m. by 60 m has a gravel path 1.5 m wide all round it on the inside. Find the cost of gravelling the path at 65 paise per sq. metre ?
Options- A. Rs. 345.15
- B. Rs. 245.1
- C. Rs. 234.18
- D. Rs. 456.65 Discuss
- 10. The perimeter of an isosceles triangle is 32 cm and each of the equal sides is 5/6 times of the base. What is the area (in cm2 ) of the triangle ?
Options- A. 39
- B. 48
- C. 57
- D. 64 Discuss
Area problems
Search Results
Correct Answer: 3
Correct Answer: 288 sq.cm
Explanation:
Length of the thread is 36 cms.
length wise twice breath wise once then totally thrice.
so 36/3 = 12.
so length is 12 x 2 = 24 cms
breath is 12 cms
Area of the book = length x breath = 24 x 12 = 288 sq.cm
Correct Answer: 38.57 cm
Explanation:
We know that perimeter of rectangle = 2(l+b) = 2(8+7)= 30cm
Given perimeter of square is twice the perimeter of rectangle = 2(30) = 60cm
Therefore, side of the square is = 1/4 x 60 = 15cm
Circumference of the required semicircle =
=
= 23.57 + 15 = 38.57cm.
Correct Answer: 6:5
Explanation:
Required ratio =
Correct Answer: 22m/s
Explanation:
let each wheel make x revolutions per sec. Then
distance moved by smaller wheel in 3 revolutions
=
speed of smaller wheel = m/s = 22m/s
Correct Answer: 60m
Explanation:
let breadth = x then length = x+20
perimeter = 5300/26.50 = 200m
2(x+20+x) =200 => 4x+40 =200
x = 40 and length = 40+20 = 60m
Correct Answer: 15:16
Explanation:
Correct Answer: 16:5
Explanation:
Area of a square SxS = 1024 => S = 32 cm
Length of the rectangle = 32x2 cm = 64 cm
Breadth of the rectangle = 32 - 12 = 20 cm
Required ratio = 64 : 20 = 16 : 5
Correct Answer: Rs. 345.15
Explanation:
area of the plot = 120m x 60m = 7200 sq.m
area of plot excluding gravel = 117m x 57m = 6669 sq.m
area of gravel = 7200 sq.m - 6669 sq.m = 531 sq.m
cost of building it = 531 sq.m x 65 ps = 34515 ps
In Rs. = 34515/100 = Rs. 345.15.
Correct Answer: 48
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