If the diagonals of a rhombus are 24cm and 10cm the area and the perimeter of the rhombus are respectively.

Q: If the diagonals of a rhombus are 24cm and 10cm the area and the perimeter of the rhombus are respectively.

Area = 1 2 * d i a g o n a l 1 * 1 2 d i a g o n a l 2 = 1 2 * 24 * 10 sq.cm 1 2 * d a i g o n a l 1 = 1 2 * 24 = 12 c m 1 2 * d i a g o n a l 2 = 1 2 * 10 = 5 c m side of a rhombus = (12)² + (5)² = 169 => AB = 13cm

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13

Correct Answer: 13

Explanation:

Area = $\frac{1}{2} * d i a g o n a l 1 * \frac{1}{2} d i a g o n a l 2$ = $\frac{1}{2} * 24 * 10$ sq.cm

$\frac{1}{2} * d a i g o n a l 1 = \frac{1}{2} * 24 = 12 c m$

$\frac{1}{2} * d i a g o n a l 2 = \frac{1}{2} * 10 = 5 c m$

side of a rhombus = (12)² + (5)² = 169 => AB = 13cm

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