Take a square of side 4cm and a rectangle having l=6cm and b=2cm
then perimeter of square = perimeter of rectangle
area of square = 16 sq.cm
area of rectangle = 12 sq.cm
Hence a >b
Let each side of the square be a. Then, area = .
New side =
. New area =
=
Increase in area =
Increase% =
% = 56.25%.
a : b =(1/2 * x * H) : (1/2 * y * h)
bxH = ayh => H/h =ay/bx
Hence H:h = ay:bx
area of theplot = 110 * 65 = 7150 sq.m
area of the plot excluding the path = (110-5)* (65-5) = 6300 sq.m
area of the path = 7150 - 6300 =850 sq.m
cost of gravelling the path = 850 x (80/100) = 680 Rs
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = (41 x 41) sq.cm
Required number of tiles =1517 x 902/(41 x 41) = 814.
Area of field = = 96x sq.m
96x = 1440 => x = = 15
Hence, the length of longer parallel side = 5x = 75m
when folded along the breadth
we have 2(l/2 +b) = 34 or l+2b = 34...........(1)
when folded along the length, we have 2(l+b/2)=38 or 2l+b =38.....(2)
from 1 &2 we get l=14 and b=10
Area of the paper = 14*10 = 140 sq cm
P = 4 x s
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