From a container, 6 liters milk was drawn out and was replaced by water. Again 6 liters of mixture was drawn out and was replaced by the water. Thus the quantity of milk and water in the container after these two operations is 9:16. The quantity of mixture is:

Correct Answer: 5 litres

Correct Answer: 5:3

Correct Answer: 2:3

Correct Answer: 13 and 27

Correct Answer: 83.33 ml

Explanation:

Profit (%) = 9.09 % = 1/11

 

Since the ratio of water and milk is  1 : 11,

 

Therefore the ratio of water is to mixture = 1:12

 

Thus the quantity of water in mixture of 1 liter = 1000 x (1/12) = 83.33 ml

Correct Answer: 22 lit

Explanation:

Let the capacity of the pot be 'P' litres.
Quantity of milk in the mixture before adding milk = 4/9 (P - 8)
After adding milk, quantity of milk in the mixture = 6/11 P.
6P/11 - 8 = 4/9(P - 8)
10P = 792 - 352 => P = 44.

The capacity of the pot is 44 liters.

Correct Answer: 91 liters

Explanation:

         Milk             Water 

         74%             26%        (initially) 

         76%             24%        ( after replacement) 

 

  Left amount = Initial amount  1 - r e p l a c e d a m o u n t t o t a l a m o u n t 

   24  = 26 1 - 7 k

=> k = 91 

Correct Answer: 80 lit

Explanation:

From the given data,

let the initial quantity of the mixture = 5x

Then,

$$\begin{gathered} 2 x - 16 3 x - 24 + 40 = 1 4 \\ 8 x - 64 = 3 x + 16 \\ 5 x = 80 \\ x = 16 lit \end{gathered}$$

 

Then the initial quantity of the mixture = 5x = 5 x 16 = 80 lit.

Correct Answer: 120 liters

Explanation:

W i n e ( l e f t ) W a t e r ( a d d e d ) = 343 169

 

It means    W i n e ( l e f t ) W i n e ( i n i t i a l a m o u n t ) = 343 512   ? 343 + 169 = 512

 

Thus ,       

343 x = 512 x 1 - 15 K 3

 

  ? 343 512 = 7 8 3 = 1 - 15 k 3

 

=> K = 120

Thus the initial amount of wine was 120 liters.

Correct Answer: 9:1

Explanation:

Milk = 3/5 x 20 = 12 liters, water = 8 liters

 

If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.

 

Remaining milk = 12 - 6 = 6 liters

Remaining water = 8 - 4 = 4 liters

 

10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.

 

The ratio of milk and water in the new mixture = 16:4 = 4:1

 

If the process is repeated one more time and 10 liters of the mixture are removed,
then amount of milk removed = 4/5 x 10 = 8 liters.

 

Amount of water removed = 2 liters.

 

Remaining milk = (16 - 8) = 8 liters.

Remaining water = (4 -2) = 2 liters.

 

Now 10 lts milk is added => total milk = 18 lts

 

The required ratio of milk and water in the final mixture obtained

 

= (8 + 10):2 = 18:2 = 9:1.