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A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold?

Correct Answer: 50 l

Explanation:

Let the tin contain 5x litres of liquids


5 x   -   45   x   4 5 5 x   -   45   x   1 5   +   45   =   2 5


=> 5(4x - 36) = 2(x + 36)


=> 20x - 180 = 2x + 72


=> x = 14 litres


Hence, the initial quantity of mixture = 70l


Quantity of liquid B


70   -   45   x   1 5   +   45  


= 50 litres.


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