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At a dinner party every two guests used a bowl of rice between them, every three guests used a bowl of dal between them and every four used a bowl of meat between them. There were altogether 65 dishes. How many guests were present at the party ?

Correct Answer: 60

Explanation:

Let,


no. of rice bowl = x
no. of dal bowl = y
no. of meat bowl = z


Then, x + y + z = 65 ....(1)


Also given that, 2x = 3y = 4z


substituting value of y & z in terms of x i.e. y = 2x/3 and z = x/2 in eq (1),
We get x = 30.


As 1 rice bowl is shared between 2 guests,
Therefore, there are 60 guests.


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