Let,
no. of rice bowl = x
no. of dal bowl = y
no. of meat bowl = z
Then, x + y + z = 65 ....(1)
Also given that, 2x = 3y = 4z
substituting value of y & z in terms of x i.e. y = 2x/3 and z = x/2 in eq (1),
We get x = 30.
As 1 rice bowl is shared between 2 guests,
Therefore, there are 60 guests.
Let x% of y = y% of A, then
? xy / 100 = yA/100
? A = (xy/100) x (100/y) = x
Let 371/2% of A = 900
? {(75/2) x A} x 100 = 900
? A = (900 x 2 x 100) / 75 = 2400
So, 621/2% of A = (125/2) x (1/100) x 2400 =1500
Let A - 6% of A = AB.
? (94 x A) / 100 = AB
? B = 0.94
Let original price = Rs. 100
? Increase price = Rs. 160
? Decrease on Rs. 160 = Rs. 60
? Decrease on Rs. 100 = (60/160) x 100 % = 371/2%
?(3.6/100) x 40
= ?1.44 = 1.2
Minimum passing marks = 50 + 50 = 100
Let the total marks = x
Then, 50% of x = 100
? x = (100/50) x 100 = 200
Profit or loss percent = ab/100 %
= (20 x 20)/100 %
= -4%
5% of 50% of 500
= (5/100) x (50/100) x 500
= 12.5
Let the required amount of money be N.
Then, N x 25% = 180 x 121/2%
? N = (180 x 12.5)/25
= ? 90
Monthly income of a person = ? 5000
Increment in income = (30/100) x 5000 = 1500
New income = 5000 + 15000 = ? 6500
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