Let,
no. of rice bowl = x
no. of dal bowl = y
no. of meat bowl = z
Then, x + y + z = 65 ....(1)
Also given that, 2x = 3y = 4z
substituting value of y & z in terms of x i.e. y = 2x/3 and z = x/2 in eq (1),
We get x = 30.
As 1 rice bowl is shared between 2 guests,
Therefore, there are 60 guests.
∴ x = 2.
∴ | a + b | = | 12 | ⟹ | ❨ | 1 | + | 1 | ❩ | = | 12 |
ab | 35 | b | a | 35 |
∴ Sum of reciprocals of given numbers = | 12 |
35 |
LCM of 2, 3, 7 is 42.
=> (700 ? 300)/42 = 9 22/42 => 9 Numbers.
To find the largest 4 digit number exactly divisible by 88,
We should divide the largest possible 4 digit number by 88, and if we get any remainder than subtract it from that largest number.
The largest possible 4 digit number is 9999
Now,
88) 9999 (113
88
_______
119
88
_______
319
264
_______
55
_______
Therefore, the largest 4 digit number exactly divisible by 88 is given by
9999 - 55 = 9944.
The pattern is , ,
The next number =
i.e. 17
Probability of left handed = 4/5
total student = 40
total left handed = 40 x(4/5)
= 32
Ans.
540 = 3240/6
108 = 540/5
27 = 108/4
? = 27/3, i.e. ? = 9
Let the three consecutive odd numbers be x, x+2, x+4
Then,
x + x + 2 + x + 4 = 93
=> 3x + 6 = 93
=> 3x = 87
=> x = 29 => 29, 31, 33 are three consecutive odd numbers.
Therefore, the middle number is 31.
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