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- Question
What was the day on 31st Dec,2011?
Options- A. Monday
- B. Saturday
- C. Sunday
- D. Friday
- Correct Answer
- Saturday
- 1. Which of the following year is a leap year?
Options- A. 2500
- B. 1700
- C. 1900
- D. 2400 Discuss
- 2. The calendar of the year 2006 was used before in the year?
Options- A. 1990
- B. 1995
- C. 2002
- D. 2000 Discuss
- 3. If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
Options- A. Tuesday
- B. Wednesday
- C. Sunday
- D. Friday Discuss
- 4. Akarsh's birthday is on Saturday 29th July. On what day of the week will be Ojas's Birthday in the same year if Ojas was born on 12th August?
Options- A. Wednesday
- B. Friday
- C. Saturday
- D. Sunday Discuss
- 5. How many days are there in k weeks k days ?
Options- A. 8+k days
- B. 7+1k days
- C. 8k days
- D. 7/k days Discuss
- 6. Divyansh's birthday is on Sunday 16th July. On what day of the week will be Shaan's Birthday in the same year if Shaan was born on 1st August?
Options- A. Tuesday
- B. Monday
- C. Wednesday
- D. Sunday Discuss
- 7. Gurkiran's birthday is on Sunday 21st May. On what day of the week will be Shreyas's Birthday in the same year if Shreyas was born on 14th November?
Options- A. Tuesday
- B. Wednesday
- C. Friday
- D. Saturday Discuss
- 8. What was the day of the week on 28th May, 2006?
Options- A. Thrusday
- B. Friday
- C. Saturday
- D. Sunday Discuss
- 9. From the following years,which is not a leap year ?
Options- A. 1996
- B. 1984
- C. 1863
- D. 2004 Discuss
- 10. April 19th, 1986 falls on which day?
Options- A. Saturday
- B. Wednesday
- C. Thursday
- D. Friday Discuss
Calendar problems
Search Results
Correct Answer: 2400
Explanation:
For a century year,it is divided by 400 and leaving a ramainder of 0 results a leap year. So,2400 when divided by 400 leaves a remainder 0.
Correct Answer: 1995
Explanation:
Given year 2006, when divided by 4 leaves a remainder of 2.
NOTE: When remainder is 2, 11 is subtracted to the given year to get the result.
So, 2006 - 11 = 1995
Correct Answer: Sunday
Explanation:
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005.
So it has 1 odd day only.
The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
6th March, 2004 is Sunday (1 day before to 6th March, 2005).
Correct Answer: Saturday
Correct Answer: 8k days
Explanation:
As we know that a week has 7 days,
k weeks k days = (7k + k) days = 8k days.
Correct Answer: Tuesday
Correct Answer: Tuesday
Correct Answer: Sunday
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days
Jan. Feb. March April May
(31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Correct Answer: 1863
Explanation:
NOTE: When a year leaves a remainder 0 when divided by 4,then it is a leap year.
Here, 1863 divided by 4 doesnot give a remainder 0.
So, 1863 is not a leap year.
Correct Answer: Saturday
Explanation:
19th April, 1986 = (1985 years + Period from 1.1.1986 to 19.4.1986)
Odd days in 1600 years = 0
Odd days in 300 years = 1
85 years has 21 leap years + 64 ordinary years.
Number of odd days in 85 years =( 21 x 2 + 64) = 1 odd day.
Jan. Feb. March April
(31 + 28 + 31 + 19) = 109 days
109 days = 15 weeks + 4 days= 4 odd day.
Total number of odd days = (1 + 0 + 1 + 4) = 6.
Given day is Saturday.
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