Assume Hebah has Rs. M
Since 25% more money at Poonam
=> Money at Poonam = M + (25% of M)
=> Money at Poonam = M + 0.25M = Rs. 1.25M
Money with Navaneet is thrice the money with Poonam,
=> Money at Navaneet = 3(1.25M) = Rs. 3.75M
Now, sum of all Money = (M + 1.25M + 3.75M) = Rs. 6M
But given the average of the money is Rs. 350
=> 6M/3 = 350
=> 2M = 350
=> M = 350/2 = Rs. 175
=> Amount of money Navaneet has = Rs. 3.75M = 3.75 x 175 = Rs. 656.25.
The third proportional of two numbers p and q is defined to be that number r such that
p : q = q : r.
Here, required third proportional of 10 & 20, and let it be 'a'
=> 10 : 20 = 20 : a
10a = 20 x 20
=> a = 40
Hence, third proportional of 10 & 20 is 40.
Numbers of students in section A = x
? Numbers of students in section B and C = (100 ? x)
? x 70 + (100 ? x) 87.5 = 84 100
=> 70x + 87.5 100 ? 87.5x = 8400
=> 8750 ? 17.5x = 8400
=> 17.5x = 8750 ? 8400 => x = 20.
Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)]
= Rs. (120 - 94) = Rs. 26.
let the price of one book be Rs. x
Then, the price of other book = Rs. (x + 60% of x) = Rs.(x+(3/5)x) = Rs. (8/5)x
So, x+(8/5)x =26 <=> x =10
The prices of the two books are Rs. 10 and Rs. 16
Given number of boxes = 14
Number of workers = 4
Now, number of whole boxes per worker = 14/4 = 3.5
Hence, number of whole boxes per each coworker = 3
Given Five boxes of bananas sell for Rs. 30.
=> 1 Box of Bananas for = 30/5 = Rs. 6
Then, for Rs. 9
=> 9/6 = 3/2 = 1.5
Hence, for Rs. 9, 1.5 box of bananas can buy.
Marks in English = 85×7 ? 83×6
= 595 ? 498
= 97
We Know that sum of the n natural numbers =
Then sum of 50 natural numbers= = 1250
Average of the 50 natural numbers = = 25.5
Excluded number = (27 x 5) - (25 x 4) = 135 - 100 = 35.
Let x, x+2, x+4, x+6, x+8 and x+10 are six consecutive odd numbers.
Given that their average is 52
Then, x + x+2 + x+4 + x+6 + x+8 + x+10 = 52×6
6x + 30 = 312
x = 47
So Product = 47 × 57 = 2679
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