Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter = 5300 m = 200 m. 26.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m.
let the diagonals of the squares be 2x and 5x respectively
ratio of their areas = = 4:25
Area of a square with side a = a² sq unts
Area of a triangle with base a = (1/2) * a * h sq.unts
a² =1/2 *a *h
=> h = 2a
altitude of the triangle is 2a
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