Let us assume her house is situated at point A.
Draw a figure of movement of Radhika.
Draw the figure of movement with the help of given below direction graph.
A person starts from a point A and travels 3 km East - Wards to B. Then he turns left and travels 9 km to reach C.
He again turns left and travels 15 km and reaches his destination D.
The movements of the person are as shown in Figure
Clearly, AB = 3 km, BC = 3AB = (3 × 3) km = 9 km, CD = 5AB = (5 × 3) km = 15 km,
Draw AE ? CD.
Then, CE = AB = 3 km
AE = BC = 9 km
DE = (CD ? CE) = (15 ? 3) km = 12 km.
In triangle AED, AD2 = AE2 + DE2
or AD2 = 92 + 122
or AD2 = 81+ 144
or AD2 = 225
or AD2 = 152
AD = 15
Required distance = AD = 15 km
The movements of Amit are as shown in Fig (P to Q, Q to R and R to S).
Clearly, his final position is S which is to the South ? East from the starting point P.
Namita walks 14 meters towards west from starting point S.
(Assume the starting point is S).
Then she turns to her right and walks 14 meters.
And then turns to her left and walks 10 meters.
Again turning to her left she walks 14 meters.
Required answer: DA + SA = 10 + 14 = 24m
First and second move will be in clockwise and 3rd move will be anticlockwise.
There is two possibilities for drawing a figure for the river.
First possibilities,
First draw a figure for the river in the direction west to east then move to left in circle facing West to East direction and made half circle. Next turn to left at right angle.
Second possibilities,
First draw a figure for the river in the direction west to east then move to left in circle facing East to West direction and made half circle. Next turn to left at right angle.
Draw a figure first when man is moving in clockwise direction then for anticlockwise. The man will be finally standing in North East position as explain in below figure.
First move to north direction, then turn right, again turn right without moving from the position than turn left and move.
Draw a figure.
Rohan walks a distance of 3 km towards North.
Then turns to his left and walks for 2 km.
He again turns left and walks for 3 km.
At this point he turns to his left and walks for 3 km.
The movements of Maya from T to R are as shown in Figure.
Distance between T and R = TR = TU + UR = TU + PW + QV = ( 4 + 3 + 1) ft = 8 ft.
The movements of Sanjeev from A to F are as shown in Figure Clearly,
Sanjeev's distance from starting point A
= AF = (AB + BF) = AB + ( BE ? EF ) = AB + (CD ? EF)
= [10 + (20 ? 10)] m = (10 + 10) m = 20 m.
Also, F lies to the South of A. So, Sanjeev is 20 meters to the south of his starting point.
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