Rohan walks 3 km North, then 2 km West, then 3 km South, then 3 km East. How far from the starting point is he now?

Introduction / Context:The path forms a near-rectangle with one side longer on the final East leg. We compute net displacements on each axis and then the straight-line distance to the origin.

Given Data / Assumptions:

• 3 km North → y = +3.
• 2 km West → x = −2.
• 3 km South → y back to 0.
• 3 km East → x = −2 + 3 = +1.

Concept / Approach:End point: (1, 0). Distance to origin is simply the absolute x-offset.

Step-by-Step Solution:Final coordinates: (1, 0).Distance = sqrt(1^2 + 0^2) = 1 km.

Verification / Alternative check:North/South cancel; net East = 1 km.

Why Other Options Are Wrong:2/3/5 km do not reflect the computed net offset.

Common Pitfalls:Forgetting that the North and South legs cancel exactly.

Final Answer:1 KM