The year 2004 is a leap year. It has 2 odd days. The day on 8th February, 2004 is 2 days before the day on 8th February, 2005.
Hence, this day is Sunday
Final Price = 25 x (1 + 20/100) x (1 + 40/100)
=Rs.25 x 1.2 x 1.4
= Rs. 42
NA
Here, n1 = 5, n2 = 10, n3 = 15, a1 = 25, a2 = 50, a3 = 35
According to the formula,
Average price = (n1a1 + n2a2 + n3a3) / (n1 + n2 + n3)
= (5 x 25 + 10 x 50 + 15 x 35) / (5 + 10 + 15)
= (25 + 100 + 105) / (1 + 2 + 3)
= 230/6
= ? 38.33
Series Pattern
(15 x 11), (15 x 13), (15 x 17), (15 x 19), (15 x 23), (15 x 29)
? Missing term = (15 x 23) = 345
Length of the train = 280 m
Length of the platform = 280 x 3 = 840 m
Taken time = 6 min 40 s = (360 + 40) s = 400 s
? Required speed = Distance / Time = (840 + 280)/400
= 1120/400 = 2.8 m/s
A's 1 day's work = 1/18
B's 1 day's work = 1/9
(A + B)'s 1 day's work = 1/9 + 1/18 = 3/18 = 1/6
Radio of times taken = (1/3) : (1/4) = 4 : 3
A's 5 days' work = (1/15) x 5 = 1/3
Remaining work = 1 - (1/3) = 2/3
? (A + B)'s 1 day's work
= (1/15) + (1/10)
= (2 + 3(/30
= 5/30
= 1/6
? 2/3 work will be finished by (A + B) in (2/3) x 6 days or in 4 days .
? Total time taken = (5 + 4) days = 9 days
Given Exp. = log927 - log279
= log27 / log9 - log9 / log27
= 3log3 / 2log3 - 2log3 / 3log3
= 3/2 - 2/3 = 5/6
1014 x 986 = (1000 + 14 ) x (1000 -14)
= (1000)2 - (14)2
= (1000000 - 196) = 999804 .
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