Three numbers can be selected and arranged out of 10 numbers in 10P3 ways 10!/7! = 10 x 9 x 8
Now, this arrangement is restricted to a given condition that first number is always less than the second number and second number is always than the third number. Thus, three numbers can be arranged among themselves in 3! ways.
Hence, required number of arrangement = (10 x 9 x 8)/(3 x 2)
= 120 ways
If A runs 600 m, B runs 600 - 60 or, 540 m.
If A runs 400 m, B runs = 540 x 400 / 600 = 360 m.
Now, when B runs 500 m, C runs 500 - 50 = 450 m.
? When B runs 360 m, C runs = 450 * 360 / 500 = 324 m
? A beats C by 400 - 324 = 76 m.
Let Y = 0.15 / (0.5 / 15)
= (15/100) / [(5/100) / 15)
= 4.5
Putting arbitrary values of a and b.
IIIustration 1:
Let a = 9 and b = 8
HCF (8 + 9, 9 - 8)
HCF (17, 1) = 1
IIIustration 2:
Let a = 23 and b =17
HCF (17 + 23, 23 -17)
HCF ( 40, 6) = 2
Hence, HCF (a + b, a - b) can either be 1 or 2.
5358 x 51 | = 5358 x (50 + 1) |
= 5358 x 50 + 5358 x 1 | |
= 267900 + 5358 | |
= 273258. |
2079 is divisible by each of 3, 7, 9, 11.
Monthly sale = yearly sale / 2
= 132000 / 2
= ? 11000
June's sale = monthly sale / 2
= 11000 / 2
= ? 1000
Given that 0.8 x A = 0.09 x B
? A/B = 0.09/0.8 = 9/80
? A : B = 9 :80
For an income of Rs. 5, investment = Rs. 100
For an income of Rs. 4, investment = Rs. (100/5) x 4 = Rs. 80
For the product of 3.5413 x 2.1
Consider 35413 x 21 = 743673
Total decimal places = 4 + 1
? 3.5413 x 2.1=7.43673
? In 2/3h, 1 article is made.
? In 1h, 3/2 article are made.
? In 71/2 = 15/2h, 3/2 x 15/2 = 45/4 article are made.
? Required articles = 45/4 = 112/4
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