Find the number of ways of arranging the host and 8 guests at a circular table, so that the host always sits in a particular seat?

Total number of persons = 9
Host can sit in a particular seat in one way .
Now, remaining positions are defined relative to the host .
Hence, the remaining can sit in 8 places in ⁸P₈ = 8! ways.
∴ The number of required arrangements = 8! x 1 = 8! = 8! ways