Since, the 1st students can have any day as his birthday and according to the question corresponding to the 1st person and 2nd the 3rd person need to have the same day as their birthday and thus probability that they have identical birthday
= 1x (1/365) x (1/365)
= 1/(365)2
Relative speed | = (x + 50) km/hr | |||||||
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Distance covered = (108 + 112) = 220 m.
∴ | 220 | = 6 | ||
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⟹ 250 + 5x = 660
⟹ x = 82 km/hr.
Multiply each term by 3 to obtain the next term. Hence, 30 is a wrong number.
Even numbers between 11 to 63
= 12,14,16,18,20,..........,62.
Clearly, this is a series of consecutive even number
According to the formula
Average of consecutive even numbers = (First number + Last number)/2
= (12 + 62)/2
= 74/2
= 37
? Rate = [(interest x 100) / (Principal x Time) ] %
? Rate = (2700 x 100) / (15000 x 3) %
? Rate = 6%
Since 6 identical machines in 1 minute can produce a total of 270 bottles.
? 1 identical machines in 1 minute can produce a total of 270 / 6 bottles.
? 10 identical machines in 1 minute can produce a total of 270 x 10 / 6 bottles.
? 10 identical machines in 4 minute can produce a total of 270 x 10 x 4 / 6 bottles.
? 10 identical machines in 4 minute can produce a total of 45 x 10 x 4 bottles.
? 10 identical machines in 4 minute can produce a total of 1800 bottles.
Speed in km/hr = speed in m/sec x (18 / 5 )
Speed in km/hr = (22.5 x 18 /5 ) km/hr
= 81 km/hr.
Then, x + y = 15 and x - y = 3 or y - x = 3.
Solving x + y = 15 and x - y = 3, we get: x = 9, y = 6.
Solving x + y = 15 and y - x = 3, we get: x = 6, y = 9.
So, the number is either 96 or 69.
Hence, the number cannot be determined.
Formula for converting from km/hr to m/s: X km/hr = | ❨ | X x | 5 | ❩ | m/s. |
18 |
Therefore, Speed = | ❨ | 45 x | 5 | ❩m/sec | = | 25 | m/sec. |
18 | 2 |
Total distance to be covered = (360 + 140) m = 500 m.
Formula for finding Time = | ❨ | Distance | ❩ |
Speed |
∴ Required time = | ❨ | 500 x 2 | ❩sec | = 40 sec. |
25 |
∴ R = | ❨ | 100 x 60 | ❩ | = 10% p.a. |
100 x 6 |
Now, P = Rs. 12000. T = 3 years and R = 10% p.a.
∴ C.I. |
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= 3972. |
According to the formula
M1D1T1/W1= M2D2T2/W2
Given M1 = 105 D1 = 25 T1 = 8 W1 = 2/5
Now let the additional men be N
Then, M2 = 105 + N, T2 = 9, D2 = 25 and W2 =1 - (2/5) = 3/5
On putting these value in the above formula
(105 x 25 x 8) / (2/5) = [(105 + N) x 25 x 9] / (3/5)
? (105 x 8) / 2 = (105 + N) x (9/3)
? 105 x 4 = (105 + N) x 3
? 105 x 4 = 105 x 3 +3N
? 3N = 105
? N = 35 men
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