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- Question
- A coin is successively tossed two times. Find the probability of getting? (1) exactly one head (2)at least one head
Options- A. 1/2 , 3/4
- B. 2/3, 1/4
- C. 1/4, 4/5
- D. 1/2, 2/3
- Correct Answer
- 1/2 , 3/4
ExplanationIn tossing a coin 2 times the sample space is 4 i,e (H, H), (H, T), (T, H), (T, T)
(1) If A1 denotes exactly one head
then A1 = {(H, T) (T, H) }
So, P(A1 ) = 2/4 = 1/2
(2) If A denotes at least one head
then A = {(H, T) (T, H) (H, H)}
? A = {(H, T) (T, H) (H, H )}
? P(A) = 3/4 - 1. The probability that a teacher will give one surprise test during any class meeting in a week is 1/5. If a student is absent twice. What is the probability that he will miss at least one test?
Options- A. 4/15
- B. 1/15
- C. 91/25
- D. 16/125 Discuss
- 2. In a throw of a coin, the probability of getting a head is?
Options- A. 1/2
- B. 1/4
- C. 1
- D. None of these Discuss
- 3. In a simultaneous throw of two coins, the probability of getting at least one head is?
Options- A. 1/2
- B. 2/3
- C. 3/4
- D. 1/3 Discuss
- 4. Three unbiased coins are tossed, what is the probability of getting exactly two heads?
Options- A. 1/3
- B. 3/4
- C. 2/3
- D. 3/8 Discuss
- 5. Three unbiased coins are tossed. What is the probability of getting at most 2 heads?
Options- A. 1/4
- B. 3/8
- C. 7/8
- D. 1/2 Discuss
- 6. In a simultaneous throw of two dice find the probability of getting a total of 8 .
Options- A. 2/9
- B. 5/36
- C. 1/6
- D. Data Inadequate Discuss
- 7. What is the probability that an ordinary year has 53 Sundays?
Options- A. 53/365
- B. 1/7
- C. 2/7
- D. 48/53 Discuss
- 8. One card is drawn at random from a pack of 52 cards. What is the probability that the card drawn is a face card?
Options- A. 4/13
- B. 1/4
- C. 9/52
- D. 1/13 Discuss
- 9. One card is drawn at random from a pack of 52 cards. What is the probability that the card drawn is either a red card or a king?
Options- A. 6/13
- B. 1/2
- C. 7/13
- D. 27/52 Discuss
- 10. What if the probability of getting a king or a queen in a single drawn from a pack of 52 cards?
Options- A. 1/26
- B. 1/13
- C. 2/13
- D. None of these Discuss
Probability problems
Search Results
Correct Answer: 1/15
Explanation:
The probability of absenting of the students in the class = 2/6 = 1/3
? The probability of missing his test = 1/5 x 1/3 = 1/15
Correct Answer: 1/2
Explanation:
Here S = {H, T}
and E = {H}
? P(E) = n(E)/n(S) = 1/2
Correct Answer: 3/4
Explanation:
S = {HH, HT, TT, TH}
and E = {HH, HT, TH }
? P(E) = n(E)/n(S) = 3/4
Correct Answer: 3/8
Explanation:
S= { HHH, HHT, HTH, THH, TTH, THT, HTT, TTT} and
E = Event of getting exactly two heads = {HHT, HTH, THH}
? P(E) = n(E)/n(S) = 3/8
Correct Answer: 7/8
Explanation:
? n(S) = (2)3 = 8
E = Event of getting 0, or 1 or 2 heads
= {TTT, TTH, THT, HTT, HHT, HTH, THH}
? n(E) = 7
? P(E) = n(E)/n(S) = 7/8
Correct Answer: 5/36
Explanation:
In a simultaneous throw of two dice
Simple Space = 6 x 6 = 36
Favorable cases are = (2, 6) (3, 5) (4, 4 ) (5, 3) (6, 2)
So, The required probability = 5/36
Correct Answer: 1/7
Explanation:
An ordinary year has 365 days i,e. 52 weeks and 1 day. So the probability that this day is a Sunday is 1/7.
Correct Answer: 4/13
Explanation:
Clearly n(S) = 52 and there are 16 face cards.
? P(E) = 16/52 = 4/13
Correct Answer: 7/13
Explanation:
Clearly n(S) = 52. There are 26 red cards (including 2 kings ) and there are 2 more kings.
Let (E) be the event of getting either a red card or a king .
Then, n(E) = 28
? P(E) = n(E) / n(S) = 28/52 = 7/13
Correct Answer: 2/13
Explanation:
Clearly, n (S) = 52, there are 4 kings and 4 queens
? P(E) = n (E) / n (S) = 8/52 = 2/13
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