The chance of throwing a total of 3 or 5 or 11 with two dics is?

5/36
1/9
2/9
19/36

Correct Answer: 2/9

Explanation:

∵ Probability for 3 = (1, 2), (2, 1) = 2/36
⇒ Probability for 5 = (1, 4), (2, 3), (3, 2), (4, 1)= 4/ 36
⇒ Probability for 11 (5, 6), (6, 5) = 2/36
∴ Reqd . Probability = 2/36 + 4/36 + 2/36 = 8/36 = 2/9

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