The second and fourth term of the HP are 1/6 and 1/14 respectively,
Hence, for the corresponding AP, the second term is 6 and fourth term is 14.
Hence a + d = 6 and a + 3d = 14
? 2d = 8
? d = 4 and a = 2
Hence, the 10th term of this AP = a + (10 -1)d
= 2 + (10 - 1)x 4 = 2 + 9 x 4
= 2 + 36 = 38
Hence, for the corresponding HP, the 10th term is 1/38.
(a + b)/2 = 25
a + b = 50
?ab = 7
ab = 49
Hence, A can either be 7 or 49.
So, 49 is the answer.
Let term = l = arn - 1 a = 5 and l = 20480
r = 20/5 = 4
? 20480 = 5 x (4)n-1
(4)n-1 = 20480/5 = 4096 = (4)6
n - 1 = 6
? n = 7
The nth term of a GP is arn - 1 ,
5th term = ar5 - 1 = ar4 = 81
1st term = a = 16
? r4 = 81/16
? r = ?81/16 = 3/2
? 4th term = ar4 - 1 = ar3 = 16 x 3/2 x 3/2 x 3/2 = 54
Given, F = 2E + 4Y ...(I)
?EY = 4?3
? EY = 48 ...(II)
and 2EY/ E + Y = 6 ? E + Y = 16 ...(III)
Now, (E -Y)2 = (E + Y)2 - 4EY
= (16)2 - 4 x 48
= 256 - 192 = 64
? E - Y = 8 ...(iv)
From Eqs. (iii) and (iv), we get
E = 12 and Y = 4
From Eq. (i) F = 2 x 12 + 4 x 4 = 40 yr
This is a GP with a = 5 , r = 15/5 = 3, n = 7
Sn = a(rn - 1 )/(r - 1)
? S15 = 5(37 - 1)/(3 - 1)
= 5/2(37 - 1)
= 5/2 (2187 - 1)
= ? 5465
T5 = a + 4d, T7 = a + 6d
? 5(a + 4d) = 7(a + 6d)
? 5a + 20d = 7a + 42d
? a = -11d
? T12 = a + 11d = - 11d + 11d = 0
So, the twelfth term is 0.
Series pattern
2 x 12, 2 x 22, 2 x 32, 2 x 42, 2 x 52, 2 x 62
? Missing term = 2 x 42 = 32
Series pattern
13 + 1, 33 + 1, 43 + 1, 53 + 1
? Missing term = 63 + 1 = 217
Series pattern
x 2 + 5, x 3 + 5, x 4 + 5, x 5 + 5,
? Missing term = 104 x 4 + 5 = 416 + 5 = 421
Series pattern
÷ 1, ÷ 2, ÷ 3, ÷ 4, ÷ 5
? Missing term = 840/1 = 840
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