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Find the fifteenth term of the arithmetic progression 3, 9, 15, 21, ....?

Correct Answer: 87

Explanation:

In the given AP,
we have a = 3, d = (9 - 3) = 6, n =15
T15 = a + (n - 1)d
= 3 + (15 -1)6
= 3 + 84 = 87


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