Distance travelled in 1 revolution = circumference of the wheel
= ?d
= ( 22/7 ) x 63
= 198 cm
So the distance travelled in 100 revolutions = 100 x distance travelled in 1 revolution
= 100 x 198 cm
= 19800 cm
= 198 m
Distance covered in one revolution = total distance travelled / total number of revolution.
= ( 88 x 1000) / 1000 m
= 88 m
We know that the distance covered in one revolution = circumference of the wheel.
? ?d = 88
? 22d / 7 = 88
? d = 28 m
Number of round = total distance / circumference of wheel.
= (4 x 1000) / ?d
= (4 x 1000) / ( 22/7 x 7/11)
= 2000
Area = ?r2 = 0.49?
? r = 0.7 m
Number of revolutions = total distance / circumference
= (1.76 x 1000) / (2 x 22/7 x 0.7)
= 400
Circumference = 2?r
= 2 x (22 / 7) x 70 cm
= 440 cm
Distance travelled in 10 revolutions = 440 x 10 cm
= 4400 cm
= 44 m
? Speed = distance / time
= 44 / 5 m/sec
= (44 / 5) x (18 / 5) km/hr
= 31.68 km/hr
? Area of square = Area of circle
? x2 = ?r2
? x/r = ??
= ? ? : 1
Let outer radius be R and inner radius be r.
Then from question
2?R - 2?r = 66
? 2? (R-r) = 66
? (2 x 22)/7 x (R - r) = 66
? (R-r) = (66 x 7) / 44
= 10.5 m
Circumference of a circular = 2?r
? 2 x (22 / 7) x r = 440
? r = [440 x (7/22) x (1/2)] = 70 m
? Radius of outer circle = (70 + 14) m
= 84 m
The Radio of areas = area of first circle : area of 2nd circle
= ?r2 / ?(3r)2
= ?r2/ 9 ?r2
= 1/9
= 1: 9
Area = (Diagonal)2 / 2 = 50
? Diagonal = 10 units
? Radius of required circle = 5 units
Its area = [? x (5)2 ] cm2
= 25? units2
Perimeter of rectangle = Circumference of circle
= 2?r
=2 x ( 22/7 ) x 42
= 264 cm
Now perimeter of rectangle = 2 x ( 6a + 5a )
? 2 x (6a + 5a) = 264
? a = 12
Smaller side of rectangle = 5a
= 60 cm
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