A circular road runs rounds a circular ground. If the difference between the circumference of the outer circle and the inner circle is 66 meters, the width of the road is?
Correct Answer: 10.5 meters
Explanation:
Let outer radius be R and inner radius be r.
Then from question
2πR - 2πr = 66
⇒ 2π (R-r) = 66
⇒ (2 x 22)/7 x (R - r) = 66
∴ (R-r) = (66 x 7) / 44
= 10.5 m
