Let the sum be P.
? SI = P/2
? P/2 = (P x 9 x 5)/100
Clearly data is inadequate.
If the sum be ? P, then
(2240 - P) = (P x 4 x 3)/100
? 2240 = 12P/100 + P
? 2240 = 112P/100
? P = (2240 x 100)/112 = ? 2000
Now, required interest,
SI = PRT/100 = [{2000 x (7/2) x (1/2)} /100]
= ? 35
Since, the two simple interest are equal.
Then, (4000 x 3 x R)/100 = (5000 x 12 x 2)/100
? R = 10%
SI = 26350 - 21250 = ? 5100
? Rate = (SI x 100) / (Principal x Time)
= (5100 x 100) / (21250 x 6)
= 4%
Let sum = P, then SI = P/5 time = 10 yr.
? Rate = (100 x P)/(P x 5 x 10) = 2%
Given, SI2 = 60, SI1 = 30, T1 = 4 yr, T2 = 8 yr
According to the question,
[(1500 x R x 8)/100] - [(1500 x R x 4)/100] = 60 - 30
? (6000 x R)/100 = 30
? R = 30/60 = 1/2 = 0.5%
Let sum = P
Then, according to the question.
SI = P/2
? P/2 = (P x 8 x 6)/100
? It is clear that data is inadequate.
Let the sum be P.
And the original rate be y% per annum.
Then new rate=(y+3)% per annum
According to question, [(P × (y+3) × 2)/100]=[(P × y × 2)/100]=300
? [(Py + 3P)/100]=[Py/100] = 150
? Py+ 3P - Py=15000
? 3P=15000
? P= 5000
Thus, the sum is Rs 5000
Let the sum be Rs 'y'
Since Simple Interest = Rs ( y / 2)
and, T = 6 yr , R = 10% per annum
So Simple Interest, SI = (P x R x T)/100
where, R = Rate
T = Time
SI= Simple Interest
now, According to problem, ( y / 2 ) = ( y x 10 x 6)/100
? (1/2)=(6/10)
? which is not true, so it is not a possible case.
As Sum = [(100 x SI)/(Time x Rate)]
here, let R =x%, T=x yr, and, SI=Rs x
? Sum=[(100 × x)/(x × x)]
=(100/x)
Let the sum be Rs 'y' and , rate of interest = R%
Simple Interest for 2 yr =Rs( 625 - 575 ) = Rs 50
? Sum of money, y=Rs( 575 - 75)= Rs 500
? R= [(100 x SI)/(Sum x Time)]
=[(100x 75)/(500 x 3)]=5 %
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