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A man invested 1/3 of his capital at 7%, 1/4 at 8% and remainder at 10%. If his annual income is Rs. 561, the capital is?

Correct Answer: Rs. 6600

Explanation:

Let the capital be Rs. P, then
(P/3) x (7/ 100) + (x/4) x (8/100) + [P - (P/3 + P/4)] x 10/100 = 561
⇒ 7P/300 + P/50 + P/24 = 561
⇒ 42P + 36P + 75P = 1009800
P = 1009800/153 = 6600


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