Scooter pricing comparison: list price Rs 28,000. Dealer A offers a flat 10% discount; Dealer B offers 12% on the first Rs 20,000 and 8% on the remaining Rs 8,000. Find the difference between their selling prices.

Introduction:
This question compares a single flat discount with tiered discounts. Compute each net discount in rupees, then subtract the resulting selling prices.

Given Data / Assumptions:

• List price (LP) = Rs 28,000.
• Dealer A: 10% on whole LP.
• Dealer B: 12% on Rs 20,000 and 8% on Rs 8,000.

Concept / Approach:
SP = LP − (discount in rupees). Tiered discounts add linearly across their slabs.

Step-by-Step Solution:
Dealer A: discount = 10% of 28,000 = 2,800 ⇒ SP_A = 28,000 − 2,800 = 25,200Dealer B: discount = 12% of 20,000 (2,400) + 8% of 8,000 (640) = 3,040 ⇒ SP_B = 28,000 − 3,040 = 24,960Difference = 25,200 − 24,960 = Rs 240

Verification / Alternative check:
The bigger discount is B’s by Rs 240, so his SP is lower by Rs 240, consistent with the arithmetic.

Why Other Options Are Wrong:

• Rs 420 / Rs 640: do not match the computed slab differences.
• None of these: incorrect since Rs 240 is attainable.

Common Pitfalls:

• Treating tiered percentages as a single average without computing slab-wise.

Final Answer:
Rs.240