Difficulty: Easy
Correct Answer: Q ∝ H^(5/2)
Explanation:
Introduction / Context:
Weirs are standard devices for measuring open-channel discharge. The triangular (V-notch) weir is especially sensitive at low flows, and its calibration follows a characteristic power law with head.
Given Data / Assumptions:
Concept / Approach:
Integrating elemental discharge across the depth of the notch opening yields Q = C_d * (8/15) * √(2 g) * tan(θ/2) * H^(5/2). Thus, the fundamental dependence is Q ∝ H^(5/2). The stronger exponent compared with the rectangular weir (3/2) makes the V-notch more sensitive to small changes in H, aiding low-flow accuracy.
Step-by-Step Outline:
Verification / Alternative check:
Calibration charts and ISO standards for V-notches reflect a 5/2 exponent in the governing formula, with C_d and angle terms as multiplicative factors.
Why Other Options Are Wrong:
H, 1/H, and H^(3/2) correspond to other devices or simplified relations; H^(7/2) overstates the head sensitivity and is not supported by the integration result.
Common Pitfalls:
Ignoring aeration (submergence reduces effective exponent), improper head measurement location, or using rectangular-weir exponents for triangular notches.
Final Answer:
Q ∝ H^(5/2)
Discussion & Comments