Master–Slave J–K Flip-Flop — Toggle Condition and Timing In a master–slave J–K flip-flop, the toggle condition (J = 1 and K = 1) implies that Q and Q' will switch to their ________ state(s) at the ________. Choose the option that correctly completes the statement for conventional edge-triggered operation.

Difficulty: Easy

Correct Answer: opposite, active clock edge

Explanation:


Introduction / Context:
The J–K flip-flop is a versatile bistable device widely used in counters and state machines. A particularly important operating case is the toggle condition, which occurs when both inputs J and K are set to logic 1. Understanding exactly when Q and its complement Q' change state, and how that relates to the clock edge in a master–slave arrangement, is essential for robust synchronous design.


Given Data / Assumptions:

  • Device: master–slave J–K flip-flop, functionally equivalent to an edge-triggered J–K FF.
  • Toggle condition: J = 1 and K = 1.
  • Edge sensitivity: the device responds at the active clock edge (rising or falling, per symbol).


Concept / Approach:
In the toggle condition, the next state is the logical complement of the present state. In a master–slave architecture, the master latch samples inputs on one clock level; the slave transfers the master’s state to the output on the opposite level, yielding an effective edge-triggered response. Therefore, the externally observed change of Q and Q' happens at the active clock edge and results in both outputs switching to their opposite states.


Step-by-Step Solution:
Assume present state Q(n). With J = K = 1, the next state is Q(n+1) = Q(n)'.In a master–slave implementation, the master captures the toggle intent during its transparent phase.At the active clock edge, the slave updates the external output to the captured next state.Thus, Q and Q' switch to their opposite states at the active clock edge.


Verification / Alternative check:
Examine the truth/characteristic table for the J–K FF: with J = K = 1, Q(next) = Q(prev)'. Timing diagrams confirm that the visible change aligns with the specified triggering edge, not with the entire clock level.


Why Other Options Are Wrong:

  • inverted, positive clock edge: “Inverted” is ambiguous and redundant; the precise phrase is “opposite” state, and the edge may be rising or falling depending on the device.
  • quiescent, negative clock edge: “Quiescent” suggests no change, contradicting toggling.
  • reset, synchronous clock edge: Toggle does not force reset; it complements the state.


Common Pitfalls:
Confusing internal latch levels with the observed edge-triggered behavior, or assuming toggling happens throughout a clock level rather than at the edge.


Final Answer:
opposite, active clock edge

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