Multiword binary addition Add the 24-bit value 0010 0110 0011 1011 0011 1100 to the 24-bit value formed by concatenating 0101 0101 0001 1110 0001 1111. Report the 24-bit sum.

Introduction / Context:
Adding wide binary words is common for addresses, checksums, and data processing. Grouping bits into nibbles (4-bit chunks) lets us use hexadecimal to streamline arithmetic and avoid carry mistakes.

Given Data / Assumptions:

• Operand 1 (24-bit): 0010 0110 0011 1011 0011 1100.
• Operand 2 (24-bit): built by concatenation 0101 0101 0001 1110 0001 1111.
• Report the full 24-bit sum.

Concept / Approach:
Convert each 24-bit operand to hexadecimal (1 hex digit per nibble), perform hex addition with proper carries, then convert the result back to binary nibble-by-nibble.

Step-by-Step Solution:
Operand 1: 0010 0110 0011 1011 0011 1100 → 0x26 3B 3C → 0x263B3C.Operand 2: 0101 0101 0001 1110 0001 1111 → 0x55 1E 1F → 0x551E1F.Hex addition: 0x263B3C + 0x551E1F = 0x7B595B.Convert back: 0x7B 59 5B → 0111 1011 0101 1001 0101 1011.

Verification / Alternative check:
Decimal cross-check: 0x263B3C = 2,501,820; 0x551E1F = 5,578,527; sum = 8,080,347 = 0x7B595B. The binary matches this hex.

Why Other Options Are Wrong:
Each incorrect option differs in one or more nibbles (for example 0x7B415B instead of 0x7B595B), indicating carry or conversion errors.

Common Pitfalls:
Mixing independent 8-bit additions without propagating carry across bytes and misreading the concatenation as separate adds rather than a single 24-bit operand.

Final Answer:
0111 1011 0101 1001 0101 1011