Logic gate notation — what does the small circle (bubble) on a gate output indicate? Choose the operation represented when a bubble is drawn on the output of a logic symbol.
-
AComparator operation
-
BOR operation
-
CNOT operation (inversion)
-
DAND operation
-
EExclusive-OR operation
Answer
Correct Answer: NOT operation (inversion)
Explanation
Introduction / Context:Schematic symbols in digital logic often include a small circle, called a bubble, on an input or output. Understanding bubble notation is crucial when reading data sheets and designing with NAND/NOR logic, because bubbles denote inversion points and change the logic function when De Morgan’s transformations are applied.
Given Data / Assumptions:
- The small circle is placed on a gate output (or sometimes input) in the logic symbol.
- Standard ANSI/IEEE logic symbols are assumed.
Concept / Approach:A bubble explicitly represents a logical NOT (inversion). When a bubble appears on the output of an AND symbol, the device is a NAND. When it appears on the output of an OR symbol, the device is a NOR. Similarly, bubbles on inputs swap active polarity (active-LOW inputs).
Step-by-Step Solution:
Recognize the bubble as an inversion indicator.Map: AND + output bubble ⇒ NAND; OR + output bubble ⇒ NOR.Therefore, the bubble corresponds to a NOT operation applied at that node.Verification / Alternative check:Compare the truth table of an AND gate to a NAND gate. A NAND is simply the complement of AND for every input combination, matching the meaning of an output inversion bubble.
Why Other Options Are Wrong:
- Comparator operation: comparators are analog/digital interface components; the bubble does not indicate comparison.
- OR operation / AND operation: the bubble is not a basic binary operator; it is an inversion modifier.
- Exclusive-OR operation: XOR has its own distinctive symbol; a bubble does not indicate XOR.
Common Pitfalls:
- Assuming a bubble indicates an active-LOW output without realizing it also changes the gate’s logic family (e.g., NAND instead of AND).
Final Answer:NOT operation (inversion)