Based on the provided data concerning the tournament performance of six different players, answer the following questions: | Player | Matches Played | Run Average | Balls Faced | Strike Rate | |---|---|---|---|---| | A | 8 | — | — | 129.6 | | B | 20 | 81 | — | — | | C | — | 38 | 400 | 114 | | D | — | — | — | 72 | | E | 28 | 55 | 1280 | — | | F | — | — | — | 66 | Important Guidelines: 1. Strike Rate is calculated as (Total Runs / Balls Faced) * 100. 2. Every player batted in every match they played. 3. Hyphens (-) indicate missing data points that must be derived to solve the problems. Determine the total number of matches that player C participated in during the tournament.
Aptitude
Average
Difficulty: Easy
Choose an option
-
A10
-
B16
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C12
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D18
-
E8
Answer
Correct Answer: 12
Explanation
### Concept & Inverse Calculation
To find the number of matches, you must first calculate the total runs using the strike rate and balls faced, then divide by the run average.
$$ \text{Total Runs} = \left( \frac{\text{Strike Rate}}{100} \right) \times \text{Balls Faced} $$
$$ \text{Matches} = \frac{\text{Total Runs}}{\text{Run Average}} $$
### Step-by-Step Solution
1. **Extract Data for C:**
- Strike Rate = 114
- Balls Faced = 400
- Run Average = 38
2. **Calculate Total Runs:**
- Total Runs = $\left( \frac{114}{100} \right) \times 400 = 114 \times 4 = 456$
3. **Calculate Matches Played:**
- Matches = $\frac{456}{38}$
- Simplify: $\frac{456}{38} = 12$
### Exam Strategy & Shortcut
Notice the multiples: $38 \times 10 = 380$. $456$ is $76$ more than $380$, which is exactly $38 \times 2$. Hence, $10 + 2 = 12$ matches.
### Common Pitfall
Misapplying the strike rate formula (e.g., dividing by strike rate instead of multiplying) will result in an incorrect total runs calculation, derailing the final step.
### Final Answer
Therefore, the correct answer is **12**.