Primary sedimentation design: What is the detention time of a circular tank of diameter d (m) and water depth H (m) receiving sewage at Q (m^3 per hour)?

Difficulty: Easy

Correct Answer: t = (π * d^2 * H) / (4 * Q) hours

Explanation:


Introduction / Context:

Detention time (also called hydraulic retention time) is a basic check in the design of primary sedimentation tanks. It represents the average time wastewater spends in the tank, influencing suspended solids removal and settling performance.


Given Data / Assumptions:

  • Circular tank of diameter d (m) and uniform water depth H (m).
  • Inflow rate Q is in m^3 per hour.
  • Completely mixed, steady-state volume calculation.


Concept / Approach:

The detention time equals tank volume divided by flow rate. For a circular tank, the volume is the area of the plan multiplied by the depth. No correction is needed for sludge storage in this simple formula; it is a geometric check.


Step-by-Step Solution:

Plan area of a circle = π * d^2 / 4.Tank volume V = (π * d^2 / 4) * H (in m^3).Detention time t = V / Q = (π * d^2 * H) / (4 * Q) hours, since Q is in m^3 per hour.


Verification / Alternative check:

Dimensional consistency: numerator (m^3) divided by Q (m^3/h) yields hours, confirming the formula's units. This aligns with standard design practice in primary clarifier sizing.


Why Other Options Are Wrong:

  • Expressions lacking the 1/4 factor ignore the circle's area formula.
  • Using d instead of d^2 or mixing minutes/hours leads to unit inconsistency.
  • Formulas with π * d * H are dimensionally incorrect for volume.


Common Pitfalls:

  • Forgetting that diameter must be squared in the area formula.
  • Mixing flow units (e.g., m^3/s vs m^3/h) and producing wrong detention times.


Final Answer:

t = (π * d^2 * H) / (4 * Q) hours

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