Primary sedimentation design: What is the detention time of a circular tank of diameter d (m) and water depth H (m) receiving sewage at Q (m^3 per hour)?
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At = (π * d^2 * H) / (4 * Q) hours
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Bt = (π * d * H) / Q hours
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Ct = (π * d^2 * H) / Q hours
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Dt = (d^2 * H) / (4 * Q) minutes
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Et = (π * d * H) / (4 * Q) hours
Answer
Correct Answer: t = (π * d^2 * H) / (4 * Q) hours
Explanation
Introduction / Context:
Detention time (also called hydraulic retention time) is a basic check in the design of primary sedimentation tanks. It represents the average time wastewater spends in the tank, influencing suspended solids removal and settling performance.
Given Data / Assumptions:
- Circular tank of diameter d (m) and uniform water depth H (m).
- Inflow rate Q is in m^3 per hour.
- Completely mixed, steady-state volume calculation.
Concept / Approach:
The detention time equals tank volume divided by flow rate. For a circular tank, the volume is the area of the plan multiplied by the depth. No correction is needed for sludge storage in this simple formula; it is a geometric check.
Step-by-Step Solution:
Plan area of a circle = π * d^2 / 4.Tank volume V = (π * d^2 / 4) * H (in m^3).Detention time t = V / Q = (π * d^2 * H) / (4 * Q) hours, since Q is in m^3 per hour.Verification / Alternative check:
Dimensional consistency: numerator (m^3) divided by Q (m^3/h) yields hours, confirming the formula's units. This aligns with standard design practice in primary clarifier sizing.
Why Other Options Are Wrong:
- Expressions lacking the 1/4 factor ignore the circle's area formula.
- Using d instead of d^2 or mixing minutes/hours leads to unit inconsistency.
- Formulas with π * d * H are dimensionally incorrect for volume.
Common Pitfalls:
- Forgetting that diameter must be squared in the area formula.
- Mixing flow units (e.g., m^3/s vs m^3/h) and producing wrong detention times.
Final Answer:
t = (π * d^2 * H) / (4 * Q) hours