Which sequence correctly shows the default subnet masks for Class A, Class B, and Class C IPv4 networks?
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A0.0.0.0, 0.0.0.1, 0.0.1.1
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B255.255.255.0, 255.255.0.0, 255.0.0.0
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C255.0.0.0, 255.255.0.0, 255.255.255.0
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D255.255.0.0, 255.255.255.0, 255.255.255.255
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E128.0.0.0, 192.0.0.0, 224.0.0.0
Answer
Correct Answer: 255.0.0.0, 255.255.0.0, 255.255.255.0
Explanation
Introduction:Legacy classful IPv4 addressing assigns default masks based on address class. Although modern networks use CIDR, knowing the defaults remains useful for exams and interpreting historical configurations.
Given Data / Assumptions:
- Class A ranges start 0–127, default mask /8 → 255.0.0.0.
- Class B ranges start 128–191, default mask /16 → 255.255.0.0.
- Class C ranges start 192–223, default mask /24 → 255.255.255.0.
Concept / Approach:Match each class to its default prefix length and derive the dotted-decimal mask. The correct order A, B, C corresponds to /8, /16, /24 respectively.
Step-by-Step Solution:1) Class A → /8 → 255.0.0.0.2) Class B → /16 → 255.255.0.0.3) Class C → /24 → 255.255.255.0.
Verification / Alternative check:CIDR generalizes these, but routers and textbooks still reference these defaults for historical context and subnetting examples.
Why Other Options Are Wrong:
- Option B: lists the masks in reverse order (C, B, A).
- Option D: includes 255.255.255.255 which is a host route/broadcast context, not a class default mask.
- Option A/E: invalid or unrelated sequences.
Common Pitfalls:Confusing class defaults with commonly deployed subnetted CIDR masks; the question asks specifically for the default classful masks.
Final Answer:255.0.0.0, 255.255.0.0, 255.255.255.0