IPv4 classes and defaults: given the IP address 201.142.23.12 (a Class C address), what is the default subnet mask that applies before any custom subnetting?

Difficulty: Easy

Correct Answer: 255.255.255.0

Explanation:


Introduction / Context:
In classical IPv4 addressing (pre–Classless Inter-Domain Routing), each address fell into a class with a default subnet mask. Recognizing the default mask for a given dotted-decimal address helps with quick network/broadcast calculations and legacy exam questions. Here, we analyze address 201.142.23.12 and identify its default mask prior to any subnetting changes.


Given Data / Assumptions:

  • Address: 201.142.23.12
  • We assume traditional classful defaults (no VLSM/CIDR overrides).
  • We seek the default mask only, not a designed subnet mask.


Concept / Approach:
Classful ranges by first octet are: Class A = 1–126 → default mask 255.0.0.0; Class B = 128–191 → default mask 255.255.0.0; Class C = 192–223 → default mask 255.255.255.0. Since 201 falls within 192–223, 201.x.y.z is Class C, so the default mask is 255.255.255.0.


Step-by-Step Solution:

Identify first octet: 201.Map 201 to class ranges: 192–223 → Class C.Recall default mask for Class C: 255.255.255.0.Select 255.255.255.0 as the correct answer.


Verification / Alternative check:
Convert 201 to binary (11001001). The leading bits for Class C are 110, which matches the 192–223 range and therefore the /24 (255.255.255.0) default network mask in classful notation.


Why Other Options Are Wrong:

0.0.0.0: not a default mask; often represents a default route or unspecified address context.255.0.0.0: Class A default; does not apply to 201.x.x.x.255.255.0.0: Class B default; does not apply to 201.x.x.x.None of the above: incorrect because 255.255.255.0 is correct.


Common Pitfalls:
Confusing classful defaults with designed subnet masks; mixing up Class B and C boundaries (191 vs 192). Remember, 201 clearly lies in Class C.


Final Answer:
255.255.255.0.

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