What was the day of the week on 17th June 1998?

Introduction / Context:
This question again focuses on determining the day of the week for a specific past date: 17th June 1998. These questions are solved using systematic calendar algorithms or by counting from a known reference date.

Given Data / Assumptions:
• Date in question: 17 June 1998.• We use the Gregorian calendar.• Standard rules for leap years apply.

Concept / Approach:
One approach is to use a known weekday for a nearby reference date (such as 1 January 1998) and count days forward. Another approach is to use a formula such as Zeller's congruence, which directly converts a date into a weekday index modulo 7.

Outline of Counting Idea:
Step 1: Determine the weekday of 1 January 1998 (which can be found to be Thursday using known methods or references).Step 2: Count days from 1 January to 17 June 1998, considering month lengths and that 1998 is not a leap year.Step 3: Convert the total number of days to odd days (modulo 7).Step 4: Shift the weekday from Thursday by that many days to find the weekday of 17 June 1998.

Carrying out this arithmetic correctly results in the weekday being Wednesday.

Verification:
Standard calendar references and online calculators confirm that 17 June 1998 was indeed a Wednesday. This matches the result from the day-of-week computation.

Why Other Options Are Wrong:
Monday, Tuesday, Friday: Each of these would correspond to a different remainder modulo 7 and do not match the detailed computation or real-world calendars.

Common Pitfalls:
Mistakes often happen in month-length counting (particularly with February) or in misidentifying which years are leap years. Also, a single off-by-one error when moving along the weekday cycle can shift the answer.

Final Answer:
17th June 1998 was a Wednesday.