Question 1

The percent increase in the gross profit was the largest in which year as compared to the previous one?

Accepted Answer

Question 2

In which year the difference between the total sales and the gross profit is the least?

Accepted Answer

As per given above table , we have Required difference = Total Sales − Gross Profit In 1990 , = 351.6 − 155.5 = 196.1; In 1991 , = 407.9 − 134.3 = 273.6 In 1992 = 380.1 − 149.9 = 230.2; In 1993 , = 439.7 − 160.5 = 279.2 In 1994 , = 485.9 − 203.3 = 282.6 Hence required answer will be 1990 .

Question 3

In which year the total production of cars of types P and Q together was equal to the total production of cars of types R and S together?

Accepted Answer

From above given table , we can see that from year 1989 to 1994 ,( P + Q ) : In 1989 = 8 + 16 = 24 , In 1990 = 20 + 10 = 30 , In 1991 = 16 + 14 = 30 , In 1992 = 17 + 12 = 29 , In 1993 = 21 + 12 = 33 , In 1994 = 6 + 14 = 20 simillary , ( R + S ) : In 1989 = 21 + 4 = 25 , In 1990 = 17 + 6 = 23 , In 1991 = 16 + 10 = 26 , In 1992 = 15 + 16 = 31 , In 1993 = 13 + 20 = 33 , In 1994 = 8 + 31 = 39 Hence, In 1993 year , the total production of cars of types P and Q together will be equal to the total production of cars of types R and S together

Question 4

The production of which type of cars was 25% of the total production of all types of cars during 1993?

Accepted Answer

Question 5

The percent increase in total production of all types of cars in 1993 to that in 1991 was?

Accepted Answer

Question 6

In which year the production of cars of all types taken together was approximately equal to the average of the total production during the period?

Accepted Answer

Question 7

During the period 1989–94, in which type of cars was a continuous increase in production?

Accepted Answer

From the values given in above table , it is clear that during the period 1989–94 , the production of S's car is continuous increase . Hence answer will be S type of cars .

Question 8

If 60% boys and 70% girls pass in their respective courses, then total pass percentage is :

Accepted Answer

∵ Total boys = 45 + 186 +120 +100 + 65 + 32 + 58 + 5 = 611 ∴ Number of boys who pass in their respective courses = 60% of 611 = 611 x 60/100 = 366.60 Total number of girls = 25 + 23 + 25 + 12 + 25 + 20 + 12 + 3 = 145 Number of girls who pass in their respective courses =70% of 145= 145 x 70/100 = 101.50 ∴ Combined pass percent = (366.6 + 101.5) x 100/(611 + 145) = 46810/756 = 61.92 = 62%

Question 9

Total number of boys studying in the college exceeds the total number of girls in the college by:

Accepted Answer

Total number of boys = 45 + 65 + 186 + 32 + 120 + 58 + 100 + 5 = 611 Total number of girls = 25 + 23 + 25 + 12 + 25 + 20 + 12 + 3 = 145 ∴ Required percentage = (611 - 145/145) x 100 ≈ 321%

Question 10

In the art faculty number of students who have opted the course of stenography is how much percent of the total student in the faculty?

Accepted Answer

Required percentage = (25 + 120) x 100/536 = 100≈ 27

Question 11

The total number of students who have opted the course of Business Management and the course of Stenography exceeds the number of students studying in typewriting course by:

Accepted Answer

∵ Number of students in Business Management course = 160 Number of students in typewriting corse = 261 Number of students in stenography corse = 215 ∴ Requied percent = (160 + 215 - 261/261) x 100 ≈ 44%

Question 12

In which of the following courses, percentage of girls is the highest?

Accepted Answer

Percentage of girls in Business Management course = (25 + 25) x 100/160 = 31.25 Percentage of girls in typewriting course = (23 + 20) x 100/261 = 16.47 Percentage of girls in stenography course = (25 + 12) x 100/215 =12.56 And percentage of girls in typewriting and stenography course = (12 + 3) x 100/120 = 12.50 Hence, it is clear from the above that percentage of girls in Business Management course is the highest,

Question 13

What is the respective ratio of the number of the adult females to the total number of female children staying in all the societies together?

Accepted Answer

In society A: Number of children = 25/100 x (250 + 350) = 1/4 x 600 = 150 Number of male children = 40/100 x 150 = 60 Number of female children = 150 - 60 = 90 In society B: Number of children = 40/100 x (400 + 150) = 2/5 x 550 = 220 Number of male children = 75/100 x 220 = 165 Number of female children = 220 - 165 = 55 In society C: Number of children = 16/100 x (300 + 275) = 4/25 x 575 = 92 Number of male children = 25/100 x 92 = 23 Number of female children = 92 - 23 = 69 In society D: Number of children = 25/100 x (280 + 300) = 1/4 x 580 = 145 Number of male children = 80/100 x 145 = 116 Number of female children = 145 - 116 = 29 In society E: Number of children = 40/100 x (180 + 250) = 2/5 x 430 = 172 Number of male children = 50/100 x 172 = 86 Number of female children = 172 - 86 = 86 In society F : Number of children = 24/100 x (325 + 300) = 6/25 x 625 = 150 Number of male children = 46/100 x 150 = 69 Number of female children = 150 - 69 = 81 Hence, total number of female children = 90 + 55 + 69 + 29 + 86 + 81 = 410 Total Number of adult female = (350 + 150 + 275 + 300 + 250 + 300) - 410 = 1625 - 410 = 1215 Hence, required ratio = 1215 : 410 = 283 : 82

Question 14

What is the respective ratio of the total number of adult males in the societies A and B together to the total number of adult males in the societies E and F together?

Accepted Answer

Total number of adult males in the society A and B= (250 + 400) - (60 + 165) = 650 - 225 = 425 Total number of adult males in the society E and F = (280 + 325) - (86 + 69) = (180 + 325) - (86 + 69) = 505 - 155 = 350 Hence, required ratio = 425 : 350 = 17 : 14

Question 15

What is the total number of female children staying in all the societies together?

Accepted Answer

Total number of female children = 410

Question 16

What is total number of members staying in all the societies together?

Accepted Answer

Number of all members = (250 + 350) + (400 + 150) + (300 + 275) + (280 + 300) + (180 + 250) + (325 + 300) + 150 + 220 + 92 + 145 + 172 + 150 = 600 + 550 + 575 + 580 + 430 + 625 + 929 = 4289

Question 17

What is the difference between the number of male children in society B and the number of male children in society F?

Accepted Answer

Male children in society B = 165 Male children in society F = 69 Hence, their difference = 165 - 69 = 96

Question 18

Number of students studying in class X from school P forms approximately what percent of the total number of students studying in class X from all schools together?

Accepted Answer

Total number of students of class X from all school = Total number of students of class X of ( School P + School Q + School R + School S + School T + School U) Total number of students of class X from all school = 144 + 143 + 165 + 168 + 150 + 140 = 910 Required percentage = Total number of students of class X of school P x 100/Total number of students of class X from all school Required percentage =144 x 100/910 = 15.82 ≈ 16%

Question 19

Total number of students studying in school T from all Classes together forms what percent of total number of students studying in school S from all classes together?

Accepted Answer

Total number of students of school T from all classes = Total number of student of (Class V + VI + VII + VIII + IX + X ) Total number of students of school T from all classes = 147 + 144 + 158 + 163 + 154 + 150 = 916 Total number of students of school S from all classes = Total number of student of ( Class V + VI + VII + VIII + IX + X ) Total number of students of school S from all classes = 159 + 142 + 149 + 140 + 140 + 142 + 168 = 900 Required percentage = 916 x 100 /900 = 101.78%

Question 20

Which class has the maximum number of students from all schools together?

Accepted Answer

Total number of students of class V from all the school = Total number of students of ( School P + School Q + School R + School S + School T + School U ) Total number of students of class V from all the school = 152 +148 + 161 + 159 + 147 + 150 = 917 Total number of students of class VI from all the school = Total number of students of ( School P + School Q + School R + School S + School T + School U ) Total number of students of class VI from all the school = 160 + 166 + 152 + 142 + 144 + 160 + = 924 Total number of students of class VII from all the school = Total number of students of ( School P + School Q + School R + School S + School T + School U ) Total number of students of class VII from all the school = 145 +150 + 140 + 149 + 158 +162 = 904 Total number of students of class VIII from all the school = Total number of students of ( School P + School Q + School R + School S + School T + School U ) Total number of students of class VIII from all the school = 156 + 155 + 145 + 140 + 163 + 160 = 919 Total number of students of class IX from all the school = Total number of students of ( School P + School Q + School R + School S + School T + School U ) Total number of students of class IX from all the school = 147 + 157 + 143 + 142 + 154 + 161 =904 Total number of students of class X from all the school = Total number of students of ( School P + School Q + School R + School S + School T + School U ) Total number of students of class X from all the school = 144 + 143 + 165 + 168 + 150 + 140 = 910 Hence, the class VI has maximum number of students.

Table Charts Questions