Question 1

For which pair of courses is the number of boys the same?

Accepted Answer

As per first graph, The number of students for course A = Total number of students x 20% As per second graph, The number of girls for course A = Total number of girls x 30% Number of boys in course 'A' = The number of students for course A - The number of girls for course A Number of boys in course 'A' = (1200 x 20/100 ) - ( 800 x 30/100 ) = 240 - 240 = 0 Similarly, Number of boys in course 'B' = (1200 x 15/100 ) - (800 x 10/100) = 180 - 80 = 100 Number of boys in course 'C' = (1200 x 5/100 ) - (800 x 2/100) = 60 - 16 = 44 Number of boys in course 'D' = (1200 x 35/100 ) - (800 x 30/100) = 420 - 240 = 180 Number of boys in course 'E' = (1200 x 12/100 ) - 800 x 14/100 ) = 144 - 112 = 32 Number of boys in course 'F' = (1200 x 13/100 ) - ( 800 x 14/100 ) = 156 - 112 = 44 Hence, number of boys in course 'C' and 'F' are same which is 44.

Question 2

For course E, the number of girls is how much percent more than the boys for course E?

Accepted Answer

For course E, Number of boys = ( 1200 x 12/100 ) - (800 x 14/100 ) = 144 - 112 = 32 Number of girls = 800 x 14/100 = 112 Required percentage = ( (112 - 32 )/32 ) x 100 = (80/32) x 100 = 250%

Question 3

For which course is the number of boys the minimum?

Accepted Answer

As per first graph, The number of students for course A = Total number of students x 20% As per second graph, The number of girls for course A = Total number of girls x 30% Number of boys in course 'A' = The number of students for course A - The number of girls for course A Number of boys in course 'A' = (1200 x 20/100 ) - ( 800 x 30/100 ) = 240 - 240 = 0 Number of boys in course 'C' = (1200 x 5/100 ) - (800 x 2/100) = 60 - 16 = 44 Number of boys in course 'E' = (1200 x 12/100 ) - 800 x 14/100 ) = 144 - 112 = 32 Number of boys in course 'F' = (1200 x 13/100 ) - ( 800 x 14/100 ) = 156 - 112 = 44 Hence, in course 'A' number of boys is minimum which is Zero.

Question 4

For course D what is the respective ratio of boys and girls?

Accepted Answer

As per first graph, The number of students for course D = Total number of students x 20% As per second graph, The number of girls for course D = Total number of girls x 30% Number of boys in course D = The number of students for course D - The number of girls for course D Number of boys = ( 1200 x 35/100 ) - ( 800 x 30/100 ) = 420 - 240 = 180 Number of girls = 800 x 30/100 = 240 Since, required ratio = 180 : 240 = 3 : 4

Question 5

What is the respective ratio of men to women working in night shifts from the Call center Industry?

Accepted Answer

As per first graph given in the question, Number of people working in night shifts from Call Center Industry = Total number of people working in industries x 32% Number of people working in night shifts from Call Center Industry = 40250 x 32/100 = 12880 As per second graph given in the question, Then Number of females working in night shifts from Call Center Industry = Number of people working in night shifts from Call Center Industry x 45% Number of women working in night shifts from Call Center Industry = 12880 x 45/100 = 5796 So, the number of men working from call center Industry = 12880 - 5796 = 7084 Hence, Required ratio = 7084 : 5796 = 11 : 9

Question 6

What is the total number of men working in night shifts from all the industries together?

Accepted Answer

Number of men working in night shifts in different industries will be as below. As per given graphs in question, Number of total people working in night shifts in IT = 40250 x 12% Number of men working in night shifts in IT = 40250 x 12% x (100% - 20% ) Number of men working in night shifts in IT = 40250 x 12% x 80% ⇒ Number of men working in night shifts in IT = 40250 x (12/100) x 80/100 ⇒ Number of men working in night shifts in IT = 3864 Similarly, Number of men working in night shifts in Sports = 80/100 x 18/100 x 40250 = 5796 Number of men working in night shifts in Call Center = 55/100 x 32/100 x 40250 = 7084 Number of men working in night shifts in Sales = 40/100 x 8/100 x 40250 = 1288 Number of men working in night shifts in Banking = 60/100 x 14/100 x 40250 = 3381 Number of men working in night shifts in Chemical Industries = 85/100 x 16/100 x 40250 = 5474 Hence, total number of men working in night shifts in different industries = 3864 + 5796 + 7084 + 1288 + 3381 + 5474 = 26887

Question 7

What is the difference between the total number of men and the total number of women working in night shifts from all the industries together?

Accepted Answer

Number of men working in night shifts in different industries will be as below. As per given graphs in question, Number of total people working in night shifts in IT = 40250 x 12% Number of men working in night shifts in IT = 40250 x 12% x (100% - 20% ) Number of men working in night shifts in IT = 40250 x 12% x 80% ⇒ Number of men working in night shifts in IT = 40250 x (12/100) x 80/100 ⇒ Number of men working in night shifts in IT = 3864 Similarly, Number of men working in night shifts in Sports = 80/100 x 18/100 x 40250 = 5796 Number of men working in night shifts in Call Center = 55/100 x 32/100 x 40250 = 7084 Number of men working in night shifts in Sales = 40/100 x 8/100 x 40250 = 1288 Number of men working in night shifts in Banking = 60/100 x 14/100 x 40250 = 3381 Number of men working in night shifts in Chemical Industries = 85/100 x 16/100 x 40250 = 5474 Hence, total number of men working in night shifts in different industries = 3864 + 5796 + 7084 + 1288 + 3381 + 5474 = 26887 Total number of men = 26887 Total number of women = 40250 - 26887 = 13363 Their difference = 26887 - 13363 = 13524

Question 8

What is the approximate average number of females working in night shifts from all the industries together?

Accepted Answer

Total number of female employee = 13363 Required average number of females = 13363/6 = 2227.16 Approx 2227

Question 9

The number of women from the sports industry are what percent of the total number of people working in the night shifts from all the industries together?

Accepted Answer

Number of women from Sports Industry = (20/100) x (18/100) x 40250 = 1449 Required percentage = (1449/40250) x 100 = 3.6%

Question 10

What should be the central angle of the sector for the cost of the raw material?

Accepted Answer

Required central angle = Total angle x % of raw material Required central angle = 360° x 16/100 = 57.6°

Question 11

If the miscellaneous charges are Rs. 6000, the advertisement charges are:

Accepted Answer

Here, miscellaneous charges for 4% = 6000 Then advertisement charges for 18% = 6000 x 18/4 = Rs. 27000 Hence, required advertisement charges = Rs. 27000

Question 12

Commission on the steel is less than the advertisement charges by

Accepted Answer

Required percentage = (Advertisement charges % - Commission charges%) x 100/ Advertisement charges Required percentage = (18 - 15 ) x 100/18 = 3 x 100 /18 = 100/6 = 162/3%

Question 13

If the cost of production is Rs. 17500, the commission is :

Accepted Answer

Here, 35% = Rs. 17500 Since, 15% = (17500/35 ) x 15 = Rs. 7500 Hence, required commission = Rs. 7500

Question 14

If 5500 kg are produced, miscellaneous expenditures amount to Rs. 1848 and manufacturer's profit is 25% then selling price per kg steel is :

Accepted Answer

Here, miscellaneous expenditures amount 4% = Rs. 1848 Then, total expenditures amount for all 100% = 1848 x 100/4 = Rs. 46200 Hence, cost of 5500 kg = Rs. 46200 then cost of 1 kg = 46200/5500 = Rs. 8.40 Hence, S.P. per kg = 125/100 x Rs. 8.40 =Rs. 10.50

Question 15

The ratio of the land used for rice and barley is :

Accepted Answer

As per given pie-chart , we can see that The land used for rice is represented by 72° The land used for barley is represented by 36° ∴ Required ratio = rice crops : barley crops Required ratio = 72° : 36° = 2 : 1

Question 16

If the production of rice is 5 times that of jowar and the production of jowar is 2 times that of bajra, then the ratio between the yield per acre of rice and bajra is :

Accepted Answer

Question 17

If the total area under bajra was 300 acres, then the total area (in hundred acres) under rice and barely together is :

Accepted Answer

Question 18

The combination of three crops which contribute to more than 50% of the total area under the food crops is:

Accepted Answer

From above given chart , ∴ 100% = 360° ∴ 50% = 180° ∴ wheat + rice + maize = 72° + 72° + 45° = 189° > 180° Hence the total area of wheat , rice and maize food crops is more than 50% of the total area of given food crops .

Question 19

If 10% of the land reserved for rice be distributed to wheat and barley in the ratio 2 : 1, then the angle corresponding to wheat in the new pie-chart will be:

Accepted Answer

Question 20

Maximum expenditure of the family was on

Accepted Answer

From above given graph , According to given option in question , Maximum expenditure of the family is on food ,which is 23%.

Pie Charts Questions