In semiconductor diodes, the typical cut-in (threshold) voltages are different for germanium and silicon. Identify the correct pair for germanium and silicon, respectively, keeping common textbook values in mind for forward conduction onset.

Electronics and Communication Engineering Power Electronics Difficulty: Easy
Choose an option
  • A
    0.3 V and 0.7 V
  • B
    0.7 V and 0.3 V
  • C
    0.6 V and 0.9 V
  • D
    0.5 V and 0.7 V
  • E
    0.2 V and 0.4 V

Answer

Correct Answer: 0.3 V and 0.7 V

Explanation

Introduction / Context:Cut-in (or knee/threshold) voltage is the approximate forward voltage where a diode begins conducting appreciable current. Germanium and silicon have different bandgaps, so their forward characteristics differ noticeably in low-current circuits and rectifiers.Given Data / Assumptions:

  • Room temperature operation.
  • Common small-signal/rectifier diode behavior, not Schottky or special-purpose diodes.
  • We are after typical nominal values.
Concept / Approach:Due to a smaller bandgap, germanium diodes typically conduct at a lower forward voltage than silicon. Textbook nominal values widely used are about 0.3 V for Ge and about 0.7 V for Si under modest current levels.Step-by-Step Solution:1) Identify material: Ge vs. Si.2) Recall typical thresholds: Ge ≈ 0.3 V, Si ≈ 0.7 V.3) Match with the option set.Verification / Alternative check:Datasheets and lab experiments consistently show lower forward drops for Ge. Silicon’s higher drop is standard in rectifier and logic diode tutorials.Why Other Options Are Wrong:
  • 0.7 V and 0.3 V: reversed order.
  • 0.6 V and 0.9 V: too high for Si and unusually high for Ge.
  • 0.5 V and 0.7 V: Ge value is too high.
  • 0.2 V and 0.4 V: unrealistically low for typical room-temperature conduction points.
Common Pitfalls:
  • Confusing Schottky diodes (lower drops) with Ge/Si PN diodes.
  • Assuming constant drop; actual forward voltage depends on current and temperature.
Final Answer:0.3 V (Ge) and 0.7 V (Si) (Option A).
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