Cutoff Wavelength in a Circular Waveguide: Dependence on Physical Size For a given propagation mode (for example, the dominant TE11 mode), how does the cutoff wavelength vary with the circular waveguide's inside diameter?

Introduction / Context:Waveguides support propagation only above cutoff. In circular waveguides, each mode has a specific cutoff wavelength set by the boundary conditions and the diameter.

Given Data / Assumptions:

• We consider qualitative dependence of cutoff wavelength on diameter.
• Mode constants are fixed (e.g., TE11).

Concept / Approach:

For a circular waveguide, lambda_c = k * D for a given mode, where k is a constant determined by the root of a Bessel function equation. For the dominant TE11 mode, lambda_c ≈ 1.706 * D. Thus, cutoff wavelength scales linearly with diameter.

Step-by-Step Solution:

Verification / Alternative check:

Design charts or tables for circular waveguides list lambda_c as a constant times D for each mode.

Why Other Options Are Wrong:

Quadratic, cubic, square-root, or diameter-independent relations contradict the linear dependence defined by the modal eigenvalue.

Common Pitfalls:

Confusing cutoff wavelength with cutoff frequency (f_c ∝ 1/D). Remember f_c and lambda_c have inverse trends.

Final Answer:

Directly proportional to guide diameter.