Difficulty: Medium
Correct Answer: 1.118
Explanation:
Introduction / Context:
Flexural (bending) design often compares different cross-sections that must carry the same maximum bending moment at the same permissible bending stress. The required section modulus governs the size, and therefore the relative weight (area for unit length) follows from the geometry needed to achieve that section modulus.
Given Data / Assumptions:
Concept / Approach:
Use the section modulus Z of each shape and equate them to find the relationship between a and d. Then compute the ratio of areas A_circular / A_square, which is the ratio of flexural weights for the same bending capacity.
Step-by-Step Solution:
Z_circle = (π * d^3) / 32Z_square = a^3 / 6Set Z_circle = Z_square → (π * d^3) / 32 = a^3 / 6Solve for a in terms of d: a^3 = (3π/16) * d^3 → a/d = (3π/16)^(1/3)Areas: A_circle = π d^2 / 4 ; A_square = a^2 = ((3π/16)^(2/3)) * d^2Flexural weight ratio (circle/square) = A_circle / A_square = (π/4) / ( (3π/16)^(2/3) ) ≈ 1.118
Verification / Alternative check:
The circular section is known to be slightly less area-efficient in flexure than the optimally oriented rectangular/square section for the same Z, so the circular beam needing marginally more area (≈ 11.8%) is reasonable.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
1.118
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